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anonymous
 one year ago
What is the equation in point−slope form of the line passing through (−2, −5) and (2, 3)?
(y + 2) = −2(x + 5)
(y − 2) = 2(x − 3)
(y − 3) = 2(x − 2)
(y + 3) = −2(x + 2)
anonymous
 one year ago
What is the equation in point−slope form of the line passing through (−2, −5) and (2, 3)? (y + 2) = −2(x + 5) (y − 2) = 2(x − 3) (y − 3) = 2(x − 2) (y + 3) = −2(x + 2)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({\color{red}{ 2}}\quad ,&{\color{blue}{ 5}})\quad % (c,d) &({\color{red}{ 2}}\quad ,&{\color{blue}{ 3}}) \end{array} \\\quad \\ % slope = m slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}{\color{blue}{ y_1}}}{{\color{red}{ x_2}}{\color{red}{ x_1}}} \\ \quad \\ % pointslope intercept y{\color{blue}{ y_1}}={\color{green}{ m}}(x{\color{red}{ x_1}})\qquad \textit{plug in the values }\\ \qquad \uparrow\\ \textit{pointslope form}\)

some.random.cool.kid
 one year ago
Best ResponseYou've already chosen the best response.0hmm looks like he has it :~>jdoe can help.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0For rise over run I got 4/2 and for point slope I got y5=4/2(x+2) Is this right at all?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Im gonna guess that its D because its the only one with x+2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.04/2 would be run/rise though :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Than 2/4 ;D So than it would be y5=2/4(x+2)?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeap, just bear in mind that \(\bf \cfrac{\cancel{2}}{\cancel{4}}\iff \cfrac{1}{2}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hmmm hold the mayo... ... lemme recheck that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohhh you have a 5....hmm

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I put that because of the y1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok.. then you're correct, is 4/2 which is 2 of course :) now for the point to use could be either \(x_1,y_1\ or\ x_2,y_2\) so \(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({\color{red}{ 2}}\quad ,&{\color{blue}{ 5}})\quad % (c,d) &({\color{red}{ 2}}\quad ,&{\color{blue}{ 3}}) \end{array} \\\quad \\ % slope = m slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}{\color{blue}{ y_1}}}{{\color{red}{ x_2}}{\color{red}{ x_1}}}\implies \cfrac{\cancel{8}}{\cancel{4}}\implies 2 \\ \quad \\ % pointslope intercept y{\color{blue}{ 3}}={\color{green}{ 2}}(x{\color{red}{ 2}})\qquad \textit{plug in the values }\\ \qquad \uparrow\\ \textit{pointslope form}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But thats not an answer choice xDDDDD

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wouldn't it be positive 2 as the rise/run because the negatives both cancel?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohh yea... darn.. yes it's 3(5) = +8 and 2(2) = +4 yeap \(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({\color{red}{ 2}}\quad ,&{\color{blue}{ 5}})\quad % (c,d) &({\color{red}{ 2}}\quad ,&{\color{blue}{ 3}}) \end{array} \\\quad \\ % slope = m slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}{\color{blue}{ y_1}}}{{\color{red}{ x_2}}{\color{red}{ x_1}}}\implies \cfrac{\cancel{8}}{\cancel{4}}\implies 2 \\ \quad \\ % pointslope intercept y{\color{blue}{ 3}}={\color{green}{ 2}}(x{\color{red}{ 2}})\qquad \textit{plug in the values }\\ \qquad \uparrow\\ \textit{pointslope form}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks for all your help!!
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