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Babynini

  • one year ago

Slopes of secant (cont)

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  1. Babynini
    • one year ago
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  2. Babynini
    • one year ago
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    do I get part b by averaging the slopes of iv and v?

  3. Babynini
    • one year ago
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    @ospreytriple :) continued from the last problem

  4. Babynini
    • one year ago
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    which is 3.818382

  5. anonymous
    • one year ago
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    Examine the slopes from part A. As the x-coordinate gets closer and closer to 3, the slopes seem to approach what number? Note that some of the x-coordinates in part A approach 3 from below and some approach 3 from above.

  6. Babynini
    • one year ago
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    approaches 0?

  7. anonymous
    • one year ago
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    No. You have slopes approaching from below of 4.444444, 4.040404, 4.004004, and 4.000400. You have slopes approaching from above of 3.636363, 3.960396, 3.996003, and 3.999600. They seem to be closing in on what number?

  8. Babynini
    • one year ago
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    4

  9. anonymous
    • one year ago
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    Exactly. That's the answer to part B.

  10. anonymous
    • one year ago
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    And for part C, you now have the slope (4) and the coordinates of point P so you can figure out the equation of the line.

  11. Babynini
    • one year ago
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    Er is the equation (part c) : y=4x-16

  12. anonymous
    • one year ago
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    Correct. Excellent work.

  13. Babynini
    • one year ago
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    Yay! Thanks. hrm. It says that part a.vii is wrong. I may have rounded it incorrectly o.o

  14. anonymous
    • one year ago
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    Probably a rounding error. Just double check your calcs.

  15. Babynini
    • one year ago
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    Yeah that was it.

  16. Babynini
    • one year ago
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    Thank you :)

  17. anonymous
    • one year ago
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    You're welcome.

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