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anonymous
 one year ago
What are the magnitude and direction of the electric field produced at P by the three charges in the figure below?
anonymous
 one year ago
What are the magnitude and direction of the electric field produced at P by the three charges in the figure below?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443486683805:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[E=\frac{ kQ }{ r^2 }\] where E is electric field k is Coulomb constant Q is charge

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[E=\frac{ (8.9*10^9)Q }{ r^2 }\] how exactly do you apply the charges? I actually have no much idea

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Give me a minute. Be back.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443487357841:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Had to switch computers earlier Electric fields goes away from positive charge in the opposite direction. (repel) Electric fields goes toward negative charge in the same direction. (attract) So your diagram of the electric field would be dw:1443487695840:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait how is it known that P is positive?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0P is an electric field. The electric field relative to the charges.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Alright, about the electric field dw:1443487887846:dw is it something like that?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443488158566:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It moves in opposite direction from the charges. So if there is angle it move diagonally

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Dont worry about the movement of the charges. The question only concerns with the field not the charges. But the charges should be like this if you want to know dw:1443488272987:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Opposite charge attract Same charges repel.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Why not on that side? dw:1443488417223:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But thats not important in this problem. Lets label the electric field vectors now. E1, E2, E3 dw:1443488495113:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0First convert the cm to meters. Then use \[E _{1}=\frac{ kQ }{ r^2 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Solve for electric field one first.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443488673433:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[E=\frac{ kQ }{ r^2 }\] \[E=\frac{ (8.9*10^9)Q }{r^2 }\] I am unsure what to plug for Q and r

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yes, right units of meters and charges

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Remember, that electric field move away from the positive charge?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Which charge is E1 referring to?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443488995264:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And what is the distance from P to 5.0nC?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[E=\frac{ (8.9*10^9)(5.0*10^{9}) }{ r^2 }\] what is r? distance between P and 5nC?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0or rather, the radius so 0.02m, correct?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[E=\frac{ (8.9*10^9 )(5.0*10^{9})}{(0.02)^2 }\]\[E=111250\] seems odd

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Where did you get 0.02m?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443489283742:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443489266073:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0isn't r = radius? 0.04m = diameter

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443489310614:dw r is just distance

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[E=\frac{ (8.9*10^9)(5.0*10^{9}) }{ (0.04)^2 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No circles involved :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Show me the formula.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[E_2=\frac{ (8.9*10^9)(1.0*10^{10}) }{ (0.03)^2 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Correct. Sorry I was lagging.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Now do E3, which is the hardest one.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443489911056:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443489917026:dw\[(0.04m)^2 + (0.03m)^2 = c^2\]\[c=0.05m\]\[E_3=\frac{ (8.9*10^9)(1.0*10^{10}) }{ (0.05)^2 }\]\[E_3=356\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Since it is diagonal and makes an angle of 45 degrees dw:1443490189435:dw E3cos45 to get x component. E3sin45 to get y component

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0x= 251.7 ; y=251.7

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443490394186:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh ok, this is to find it's magnitude?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0or you can call it \[E _{3x}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Give me a second to write this.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443490526909:dw dw:1443490697051:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Add all the x and y component together \[x^2+y^2=r^2\]\ R is the resultant field or magnitude.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Direction is \[\tan^{1}( \frac{ y }{ x })\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[E_1= 27812.5\]\[E_2=988.9\]\[E_3=356\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[x=251.7 , y=251.7\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Wait so you said E_1 and E_2 are x and y?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0E1x=27812.5 E1y=0 E2x=0 E2y=988.9 E3x=251.7 E3Y=251.7

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If it goes left or down it is negative, just like the coordinate system. Up or right is positive. Refer tot eh diagram for the direction of the field. brb

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[r=\sqrt{(251.727812.5)^2+(251.7988.9)^2}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Direction is the angle in which it moves. Read what i wrote several post above.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well since it's magnitude its positive then the direction should be a positive type of slope right? dw:1443491606328:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No, you find the direction to know whether its positive or negative. It looks more negative to me. Find the direction first It can have a magnitude of 100000 and moves down diagonally (negative slope)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got to go. Go find your direction.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0y is the resultant y and x is the resultant x Same as the one you would use to find the magnitude.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443491766486:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'll be back in like 75 minutes. I can check your calculations when I get back on.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What are you doing? Use the formula.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Read every post I post. I am heading off for sure now.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\tan^{1}(\frac{ y }{ x }) = \tan^{1}(\frac{ 737.2 }{ 27560.3 }) = 0.027\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Your calculator should be radian mode and not degree.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Sorry I did not catch the mistake you made earlier. 10nC is not 1.0 x 10^10 C It is 1.0 x 10^8 C

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0For the arctan it should not be in radians, not degree. When I used it on degree mode I got your answer 0.027

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0My calculator is in radians and I get 0.027, and in degrees 1.53

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Strange. Well I am using the online right now. There might be a bug. But just use the one that doesnt have a 0.0XX something

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Redo your calculator for E2 and E3 since you wrote the C incorrectly.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Alright but once I get the answer, how can I tell the direction by just the number?