calculusxy
  • calculusxy
Scientific Notation Question!!! Question posted below...
Mathematics
  • Stacey Warren - Expert brainly.com
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katieb
  • katieb
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calculusxy
  • calculusxy
\[\huge (9 \times 10^6)^{-4}\]
calculusxy
  • calculusxy
Write each answer in scientific notation.
calculusxy
  • calculusxy
@amistre64

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More answers

anonymous
  • anonymous
9*10^-24
anonymous
  • anonymous
^ means to the power of
calculusxy
  • calculusxy
but wouldn't the 9 also be raised to the negative four power?
anonymous
  • anonymous
no, it's basically stating that the exponents would be multiplied together
anonymous
  • anonymous
the 9 is raised to the -4 as well
calculusxy
  • calculusxy
yes that's what i was thinking
calculusxy
  • calculusxy
\[\frac{ 1 }{ 9^4 \times 10^{-24} }\]
calculusxy
  • calculusxy
would that be correct?
jennithemeani
  • jennithemeani
The 9 is also raised because it is in the exponent making it (9^-4) (10^-24)
jennithemeani
  • jennithemeani
I don' think you are supposed to put it under 1
anonymous
  • anonymous
Sense it's under Scientific notation, the only number to be raised to the power of something is usually the ten
anonymous
  • anonymous
\[9^{-4}\times10^{-24}=\frac{ 1 }{ 9^4\times10^{24} }\]
anonymous
  • anonymous
what format are you trying to write this in?
calculusxy
  • calculusxy
scientific notation
anonymous
  • anonymous
ok then you wouldn't want to write them as fractions. keep it as \(9^{-4}\times10^{-24}\) and evaluate 9^-4
calculusxy
  • calculusxy
okay so that would be like 6561
anonymous
  • anonymous
1/6561 since the 4 is negative \[9^{-4}=\frac{1}{6561}=1.52\times10^{-4}\] so altogether you have \[1.52\times10^{-4}\times10^{-24}=1.52 \times 10^{-28}\]
calculusxy
  • calculusxy
so we have to add 10^{-4} and 10^{-24} together? and why?
anonymous
  • anonymous
because when you multiply terms with the same base you add the exponents \[x^a \times x^b=x^{a+b}\]
calculusxy
  • calculusxy
well i was trying to say that usually we would move the decimal over to a number that's larger than 10 and then multiply it by 10^{___} and the blank is like the # of times the decimal was moved over. then we multiply it with the original exponent that was given in the problem.
calculusxy
  • calculusxy
so i was kind of confused
anonymous
  • anonymous
yeah that's the same thing, except you add it to the original exponent, not multiply
calculusxy
  • calculusxy
okay so if we have now: \[\frac{ 4 \times 10^{-2} }{ 3.01 \times 10^{-2} }\]
calculusxy
  • calculusxy
we would just divide them and then use the same thing that we did for this problem?
anonymous
  • anonymous
yes, and since this is division, subtract the exponents
calculusxy
  • calculusxy
okay. can u hold on for like a minute while i try to solve the problem?
anonymous
  • anonymous
sure
calculusxy
  • calculusxy
would it be: 1.33 x 10^0
anonymous
  • anonymous
yes
calculusxy
  • calculusxy
thank you so much!
anonymous
  • anonymous
you're welcome :)

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