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clara1223
 one year ago
Using the Mean Value Theorem find all numbers c on the interval [0,5] that satisfy the theorem for f(x)=3*sqrt(25x^2). I have already found that (f(5)f(0))/(50)=3, and that the derivative of the function is (3x)/sqrt(25x^2). When I set that equal to 3 and solve for x I get an answer that is not in the interval so I am doing something wrong. Can someone help me?
clara1223
 one year ago
Using the Mean Value Theorem find all numbers c on the interval [0,5] that satisfy the theorem for f(x)=3*sqrt(25x^2). I have already found that (f(5)f(0))/(50)=3, and that the derivative of the function is (3x)/sqrt(25x^2). When I set that equal to 3 and solve for x I get an answer that is not in the interval so I am doing something wrong. Can someone help me?

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clara1223
 one year ago
Best ResponseYou've already chosen the best response.0@zepdrix can you help me?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1I don't get why you said so, \(\dfrac{3x}{\sqrt{25x^2}}=3\\x = \sqrt{25x^2}\) \(x^2 = 25 x^2\\2x^2 = 25\\x=\pm\dfrac{5}{\sqrt2}\) has positive one is on the interval. Am I missing something?

clara1223
 one year ago
Best ResponseYou've already chosen the best response.0Oh I didnt cancel out the 3 in the beginning and somehow I got my math wrong. I got \[\pm \frac{ 5\sqrt{3} }{ \sqrt{2} }\] Thanks!
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