owlet
  • owlet
help, I'm stuck with the question below. About Inverse Function. I just need help getting the inverse of the function.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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owlet
  • owlet
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anonymous
  • anonymous
this has to be done algebraically?
owlet
  • owlet
yeah, idk how to do it

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owlet
  • owlet
i'm not sure how to do the sqrt part along with the y^3 part
anonymous
  • anonymous
not really sure how to go about solving the equation for y, but they're basically asking you to find where y = 11. I graphed it and backed out a solution that way. not exactly efficient
owlet
  • owlet
i tried doing that also. First I planned to solve the value of x when f(x)=11 , so that I could just switch it. But I'm stuck. We're not allowed to use any devices during exams/tests/quizzes, so I wanted to learn how to do this.
anonymous
  • anonymous
I was thing a change of variable, but the equations I ended up with weren't much better than this one
anonymous
  • anonymous
i have a suggestion
anonymous
  • anonymous
set \[x^3+\sqrt{x+7}=11\] and solve for \(x\)
anonymous
  • anonymous
you can do it using algebra, but i would not there is a simpler way
owlet
  • owlet
as i've said before, that's the first thing I tried. sqrt(x+7)=11-x^3 then if I square both sides,I will still get a not so good set up which confused me.
anonymous
  • anonymous
since 11 is an integer, \(x+7\) must be a perfect square
anonymous
  • anonymous
think of a number (gotta be pretty small) that when added to 7 gives a perfect square you will probably get it on the first try
owlet
  • owlet
7+2=9, so 2?
anonymous
  • anonymous
an easy check now right?
anonymous
  • anonymous
\[2^3+\sqrt{2+7}=?\]
owlet
  • owlet
8+3=11.. so its really 2 wait that's it??
anonymous
  • anonymous
lol yeah, that's it
owlet
  • owlet
oh okay thanks.. it's like a trial and error method then

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