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owlet
 one year ago
help, I'm stuck with the question below. About Inverse Function. I just need help getting the inverse of the function.
owlet
 one year ago
help, I'm stuck with the question below. About Inverse Function. I just need help getting the inverse of the function.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this has to be done algebraically?

owlet
 one year ago
Best ResponseYou've already chosen the best response.0i'm not sure how to do the sqrt part along with the y^3 part

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0not really sure how to go about solving the equation for y, but they're basically asking you to find where y = 11. I graphed it and backed out a solution that way. not exactly efficient

owlet
 one year ago
Best ResponseYou've already chosen the best response.0i tried doing that also. First I planned to solve the value of x when f(x)=11 , so that I could just switch it. But I'm stuck. We're not allowed to use any devices during exams/tests/quizzes, so I wanted to learn how to do this.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I was thing a change of variable, but the equations I ended up with weren't much better than this one

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0set \[x^3+\sqrt{x+7}=11\] and solve for \(x\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you can do it using algebra, but i would not there is a simpler way

owlet
 one year ago
Best ResponseYou've already chosen the best response.0as i've said before, that's the first thing I tried. sqrt(x+7)=11x^3 then if I square both sides,I will still get a not so good set up which confused me.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0since 11 is an integer, \(x+7\) must be a perfect square

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0think of a number (gotta be pretty small) that when added to 7 gives a perfect square you will probably get it on the first try

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0an easy check now right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[2^3+\sqrt{2+7}=?\]

owlet
 one year ago
Best ResponseYou've already chosen the best response.08+3=11.. so its really 2 wait that's it??

owlet
 one year ago
Best ResponseYou've already chosen the best response.0oh okay thanks.. it's like a trial and error method then
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