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dtan5457
 one year ago
if f(g(x)=2x/(x+z), and g(x)=2x/(x+4)
find f(x)
dtan5457
 one year ago
if f(g(x)=2x/(x+z), and g(x)=2x/(x+4) find f(x)

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jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0is the `x+z` supposed to be `x+4` ?

dtan5457
 one year ago
Best ResponseYou've already chosen the best response.0they are both under 2x so no

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0then I'm not sure. That z is throwing me off

dtan5457
 one year ago
Best ResponseYou've already chosen the best response.0perhaps its an x+2? I mean my teacher's handwriting does look like a Z.

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0that sounds possible

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i have an answer that might work, but i think you are supposed to use inverse functions some how

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0by trial and error i came up with \[f(x)=\frac{1}{x\frac{2}{x}}\]] we can see if that works, and also clean it up a bit

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0in any case it is wrong, but i think i can fix it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lets try this one \[f(x)=\frac{1}{\frac{1}{x}\frac{2}{2x}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok one more time without me being so stupid \[f(x)=\frac{1}{\frac{1}{x}\frac{2}{x+4}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i think that actually works

dtan5457
 one year ago
Best ResponseYou've already chosen the best response.0where would a Z come up though? or is that for x+2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i used 2 with z it is too weird

dtan5457
 one year ago
Best ResponseYou've already chosen the best response.0so it would be impossible with z?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i am wagering it is 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i wonder if we can do it with differentiation though, is that part of this class?

dtan5457
 one year ago
Best ResponseYou've already chosen the best response.0this is pre calc we only did difference quotients so far

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0maybe @Zarkon has a better idea seems like it needs to use inverse functions some how but i am clogged up in any case i am almost certain the (third) answer i wrote above works, just trying to figure how to subtract 2 in the denominator

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0take the reciprocal, subtract 2 in the numerator, then take the reciprocal again of course that mess i wrote can be cleaned up without using compound fractions

dtan5457
 one year ago
Best ResponseYou've already chosen the best response.0my teacher may have wrote something wrong of some sort its only been like 2 weeks into school i doubt he would have something harder than you can solve

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0usually you are told \(f\) and \(f\circ g\) and asked to find \(g\) that you can do by finding the inverse of \(f\) and applying it this is a bit different

dtan5457
 one year ago
Best ResponseYou've already chosen the best response.0you are right in my class example we had to find g and that was fairly simple
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