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anonymous
 one year ago
x2y=8? (finding slope)
anonymous
 one year ago
x2y=8? (finding slope)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0alright the easiest way to find the slope is to convert it to slope intercept form

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry i gotta go,,, remember y=mx+b, m is the slope

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0every time I "finish" my equation it becomes wrong somehow. so far I've done 2Y=8x and divide that which gets me Y=4x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0they're saying it's wrong...

FireKat97
 one year ago
Best ResponseYou've already chosen the best response.0x  2y = 8 so you want to get it in the form y = mx + b so you can simply read off the slope

FireKat97
 one year ago
Best ResponseYou've already chosen the best response.0so try rearranging the equation and post up what you get

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0slope equals positive 1/2

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.0\[x2y=8\] One way to get the slope (as other posters have suggested) is to rearrange the equation in slopeintercept form, or \[y = mx + b\]You can then "read off" the slope (\(m\)) and the yintercept value (\(b\)). To do this, just solve your equation for \(y\): \[x2y = 8\]add \(2y\) to both sides \[x2y+2y = 8+2y\]\[x=8+2y\]add \(8\) to both sides \[x+8 = 8+8+2y\]\[x+8 = 2y\]divide both sides by \(2\)\[\frac{x}{2} + \frac{8}{2} = \frac{2y}{2}\]\[\frac{1}{2} x + 4 = y\]swap sides for conveniences \[y = \frac{1}{2} x + 4\] comparing with our slopeintercept form \(y = mx + b\) we see that \(m =\frac{1}{2}\) and so our slope is \(\frac{1}{2}\).

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.0Another approach is to just find two points on the line and use the formula for the slope of a line passing through two points: \[m = \frac{y_2y_1}{x_2x_1}\]where the line passes through points \((x_1,y_1)\) and \((x_2,y_2)\) To find out points, pick some values that will be easy to compute. \(x=0\) is usually a good one, let's try it: \[x=0,\ y = \frac{0}{2}x+4= 4\]so the point \((0,2)\) is our first point, \((x_1,y_1)\) As we have that pesky \(\frac{1}{2}\) in the formula, let's use a value of \(2\) for \(x\) for the other point to eliminate the fraction: \[x = 2, \ y = \frac{1}{2}(2) + 4 = 5\] So \((2,5)\) is our other point, \((x_2,y_2)\) Let's plug those points into the formula for the slope: \[m = \frac{y_2y_1}{x_2x_1} = \frac{54}{20} = \frac{1}{2}\] Look at that, we got the same answer. Good thing, too!

whpalmer4
 one year ago
Best ResponseYou've already chosen the best response.0sorry, I mistyped that equation for the first point in the previous post: \[x=0,\ y = \frac{0}{2}x+4= 4\]should be\[x=0,\ y = \frac{1}{2}(0)+4= 4\]
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