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marigirl

  • one year ago

Related Rates of change- Differentiation Show that:

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  1. marigirl
    • one year ago
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    Show that: \[\frac{ d }{ dx }(\frac{ v^2 }{ 2 })=\frac{ d^2x }{ dt^2 } \] Where x represents the distance traveled in t secs by a particle moving with velocity v

  2. marigirl
    • one year ago
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    \[\frac{ dx }{ dt }=v\] Could we state that?

  3. baru
    • one year ago
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    hi

  4. baru
    • one year ago
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    yes dx/dt is v

  5. baru
    • one year ago
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    differentiate dx/dt=v again with respect to time to get \[d^2x/dt^2=dv/dt\]

  6. baru
    • one year ago
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    now you can replace the right hand side of the given equation with "dv/dt". now all thats left to do, is to show that the left hand side of the equation some how reduces to dv/dt. with me so far?

  7. baru
    • one year ago
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    do you know the "chain rule" of differentiation?

  8. marigirl
    • one year ago
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    oh yup got it! thanks!

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