Write the equation of the line that passes through (2, 2) and (6, 3) in standard form.

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Write the equation of the line that passes through (2, 2) and (6, 3) in standard form.

Mathematics
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A. 4x + 4y = 6 B. x + 4y = 12 C. 4x + 4y = -12 D. x - 4y = -6
Okay so this time, the only thing thats changed is the fact that you have no longer been given the slope, but remember you can find the slope with m = (y2 - y1)/(x2 - x1) or just rise/run

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And from there you can apply the same equation you had used earlier
uhh..
Let (2, 2) and (6, 3) be (x1,y1) & (x2,y2) First find the slope m=(y2-y1)/(x2-x1) m=1/4 Then take any pt (2, 2) or (6, 3) (y-y1)=m(x-x1) Then substitute the values of m & x1&y1 x-4y+6=0
okay have you covered the equation m = (y2 - y1)/(x2 - x1)?
okay so 3-2=1 and 6-2=4
yes
yup but its (3 - 2)/(6 -2) so m becomes 1/4
indeed whats next
and now we have our slope and you can pick either of the two set of coordiantes, and reapply the formula we used in the previous question
yup so in this case (2, 2) looks like the easier coordinate to use (because smaller numbers) so you can sub this and the slop of 1/4 into (y - y1) = m(x - x1)
slope*
(y-2) =1/4 (x-2)
yup thats correct!
thats not a choice though..
Thats because they don't have fractions in the answer, so we should rearrange our equation
so to get rid of the fraction on the right hand side, we can multiply both sides of the equation by 4 for starters
4y-8=x-2
Yup, and now we simplify further by resolving the -8 on the left hand side and -2 on the right
4y=x+6
4y-x=6
yup thats correct!
thats not an answer either :/
Thats because they have multiplied the left and right hand sides by -1, so try that and tell me what you get
d
Yup
:D
Thank you!!!
No problem :)

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