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Fanduekisses
 one year ago
**CHECK MY WORK PWEASE?? **Am I doing this right? SOLVING INEQUALITY.
Fanduekisses
 one year ago
**CHECK MY WORK PWEASE?? **Am I doing this right? SOLVING INEQUALITY.

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Fanduekisses
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 3 }{ x1 }+\frac{ 2x}{ x+1 }>1\]

Fanduekisses
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 3(x+1)+2x(x1)+(x1)(x+1) }{ (x1)(x+1) } >0\]

Fanduekisses
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 3x^2+x2 }{ (x1)(x+1) }\]

Fanduekisses
 one year ago
Best ResponseYou've already chosen the best response.0I did a sign chart but I get all positive, I know I must've done something wrong because the answer is \[(\infty, 1) U (1,\infty)\]

Fanduekisses
 one year ago
Best ResponseYou've already chosen the best response.0I did a sign chart but I get all positive, I know I must've done something wrong because the answer is \[(\infty, 1) U (1,\infty)\]

Fanduekisses
 one year ago
Best ResponseYou've already chosen the best response.0@countonme123 @dan815 @Data_LG2

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2there is some mistake here, lets see if we can find it

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2first lets check the algebra

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2your numerator is wrong you wrote \[\frac{ 3x^2+x2 }{ (x1)(x+1) }\] but it should be \[\frac{ 3x^2+x+2 }{ (x1)(x+1) }\]

Fanduekisses
 one year ago
Best ResponseYou've already chosen the best response.0Ohhhhhh I see it now too lol

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2now the numerator in this case is always positive so you can ignore it

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2and \[(x+1)(x1)>0\] outside the zeros, on \(x<1\) and \(x>1\)

Fanduekisses
 one year ago
Best ResponseYou've already chosen the best response.0So I only look at x=+1 then

misty1212
 one year ago
Best ResponseYou've already chosen the best response.2zeros are at \(1\) and \(1\)

Fanduekisses
 one year ago
Best ResponseYou've already chosen the best response.0I have another question, how do you find the domain of a function that has a fraction inside a square root? As in:\[f(x)=\sqrt{\frac{ x }{ x^22x35 }}\]

Fanduekisses
 one year ago
Best ResponseYou've already chosen the best response.0I factored the denominator: (x7)(x+5)

Fanduekisses
 one year ago
Best ResponseYou've already chosen the best response.0so x cannot equal 7 or 5
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