Fanduekisses one year ago **CHECK MY WORK PWEASE?? **Am I doing this right? SOLVING INEQUALITY.

1. Fanduekisses

$\frac{ 3 }{ x-1 }+\frac{ 2x}{ x+1 }>-1$

2. Fanduekisses

$\frac{ 3(x+1)+2x(x-1)+(x-1)(x+1) }{ (x-1)(x+1) } >0$

3. Fanduekisses

$\frac{ 3x^2+x-2 }{ (x-1)(x+1) }$

4. Fanduekisses

I did a sign chart but I get all positive, I know I must've done something wrong because the answer is $(-\infty, -1) U (1,\infty)$

5. Fanduekisses

I did a sign chart but I get all positive, I know I must've done something wrong because the answer is $(-\infty, -1) U (1,\infty)$

6. Fanduekisses

@countonme123 @dan815 @Data_LG2

7. misty1212

HI!!

8. misty1212

there is some mistake here, lets see if we can find it

9. Fanduekisses

:)

10. misty1212

first lets check the algebra

11. Fanduekisses

ok

12. misty1212

ooh i see it!!

13. misty1212

your numerator is wrong you wrote $\frac{ 3x^2+x-2 }{ (x-1)(x+1) }$ but it should be $\frac{ 3x^2+x+2 }{ (x-1)(x+1) }$

14. Fanduekisses

Ohhhhhh I see it now too lol

15. misty1212

now the numerator in this case is always positive so you can ignore it

16. misty1212

and $(x+1)(x-1)>0$ outside the zeros, on $$x<-1$$ and $$x>1$$

17. Fanduekisses

So I only look at x=+1 then

18. misty1212

zeros are at $$1$$ and $$-1$$

19. Fanduekisses

Thank you! :D

20. Fanduekisses

I have another question, how do you find the domain of a function that has a fraction inside a square root? As in:$f(x)=\sqrt{\frac{ x }{ x^2-2x-35 }}$

21. Fanduekisses

I factored the denominator: (x-7)(x+5)

22. Fanduekisses

so x cannot equal 7 or -5