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sloppycanada

  • one year ago

An airplane is flying 10,000 feet above the ground at an angle of depression of 15°. How far must the plane fly in order to land? Round your answer to the nearest foot. I should be able to do this, but I'm completely stumped.

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  1. sloppycanada
    • one year ago
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    |dw:1443491626426:dw|

  2. FireKat97
    • one year ago
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    Your angle of depression isn't labelled correctly

  3. FireKat97
    • one year ago
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    |dw:1443491875565:dw|

  4. anonymous
    • one year ago
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    |dw:1443502586139:dw|

  5. sloppycanada
    • one year ago
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    -4207

  6. FireKat97
    • one year ago
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    I think you made a calculator error @sloppycanada try again

  7. anonymous
    • one year ago
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    tan 75 not negative.

  8. anonymous
    • one year ago
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    37320 ft tan75=3.7320

  9. sloppycanada
    • one year ago
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    according to my calculator, tan75 = -.420700

  10. anonymous
    • one year ago
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    take degrees ,you are working on radians.

  11. sloppycanada
    • one year ago
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    oh. well then. then it's 37,320.5, which means i go up to 37,321

  12. anonymous
    • one year ago
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    correct.

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