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credmond
 one year ago
Iterated Integral Question:
credmond
 one year ago
Iterated Integral Question:

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credmond
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443492683994:dw

credmond
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443492857641:dw

credmond
 one year ago
Best ResponseYou've already chosen the best response.0Did I set this up right?

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1Since the limits is from 1x to 1+x, I guess, the first integration should respect to y, not to x.

Loser66
 one year ago
Best ResponseYou've already chosen the best response.1They are different!! Please, check.

credmond
 one year ago
Best ResponseYou've already chosen the best response.0I am sorry! It is dydx

credmond
 one year ago
Best ResponseYou've already chosen the best response.0So I started distributing across and ended up with 7(x^3+3x^2+3x+1) +14xy +14

credmond
 one year ago
Best ResponseYou've already chosen the best response.0Am I on the right track?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.2thusfar you should have \[\large \int\limits_{x=0}^{1} \; \; \int\limits_{y=1x}^{1+x} 21x^2 + 14y\; dy \; dx\] \[\large =\int_{0}^{1} \left[ 21x^2y + 7y^2 \right]_{1x}^{1+x} \; dx\] \[\large =7 \int_{0}^{1} \left[ \left(3x^2(1+x) + (1+x)^2 \right)  \left(3x^2(1x) + (1x)^2 \right)\right] \; dx\] \(= \; \; ...\) you still have y's in there so something has gone wrong.
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