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owlet

  • one year ago

how to explain my answer?

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  1. owlet
    • one year ago
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  2. owlet
    • one year ago
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    I based the range of the inverse from ln(x)

  3. owlet
    • one year ago
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    the range of ln(x) is (-infinity, +infinity)

  4. owlet
    • one year ago
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    my inverse function is a ln function so yeah.. I'm not really good at explaining stuff. Need help with this part.

  5. baru
    • one year ago
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    i ln(0) is undefined...include that in your "range"

  6. owlet
    • one year ago
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    are you sure?

  7. owlet
    • one year ago
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    i thought that would be the domain?

  8. Loser66
    • one year ago
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    if the function is f and its inverse is f^-1, then domain of f is range of f^-1 range of f is domain of f^-1

  9. Loser66
    • one year ago
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    so, to find range of f^-1, you just find the domain of f, which is the- inside- the- square- term \(\geq 0\)

  10. Loser66
    • one year ago
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    |dw:1443495702419:dw|

  11. Loser66
    • one year ago
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    solve it.

  12. owlet
    • one year ago
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    |dw:1443495749791:dw|

  13. Loser66
    • one year ago
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    yyyyyyyyyyyyyyyyup

  14. owlet
    • one year ago
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    so that's the domain of f, which will the range of f^-1?

  15. owlet
    • one year ago
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    be**

  16. Loser66
    • one year ago
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    yes

  17. owlet
    • one year ago
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    oh okay, thanks. I think this is what baru is trying to say awhile ago.. lol sorry

  18. baru
    • one year ago
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    sorry...dont really remember range and domain, just figured that we were looking for all permitted values for "x"... anyways learnt something new :)

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