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when going around the circle , the car would accelerate radially towards the center of that circle

Yes, but how do you calculate the velocity without mass?

The radial acceleration can be a function of the velocity

I'm sorry I don't understand

mass can be found in the other dimension if you need it, the normal force is to weight

And how would you calculate normal force?

\[\vec a_c = \frac{ v^2 }{ r }\] so we can use @DanJS equation and find the max speed

Yeah haha was just going to say

Does not accelerate in vertical direction, and so F= m*a = 0 = N - mg

\[\vec F_f = \mu \vec F_N = \mu mg\]

Okay bare with me for one moment, I want to write out what I understand and what I don't understand

\[\vec F_c = \vec F_f\]

So in the equation Fâƒ— f=Î¼Fâƒ— N=Î¼mg, m=1?

Your net force = centripetal

Against the tires, so towards the center of the circle?

In above picture, the car is moving on a straight road. There is no circle, yet.

Remember, frictional force always "opposes" the direction of motion.

Yes, so if the car is move to the right the frictional force would be towards the left, correct?

moving*

Why ?

Because friction is the force trying to stop the motion opposed to it?

Ah it was much longer than that, a few things got overwritten

The answer is suppose to be 54 m/s, @ganeshie8 do you get that when you do the math?

Hey please read it agian, I have fixed left/right typoes..

Nice post @ganeshie8
Also what do you get when you solve for v for the above equation @cheska_P

I get 17.04

Hmm, what does your expression look like, can you show the algebra? \[\mu mg = \dfrac{mv^2}{r} \]

I'll try give me one second

|dw:1443502674089:dw|

Good so, \[v = \sqrt{r \mu g} \implies \sqrt{(740m)(0.40)(9.81m/s^2)}\] you got the right numbers?

yes

wait no

I'm an idiot, I had .040 not .40 for my static friction coefficient

been*

Np, make sure you read the post above explaining unbanked curves, it's pretty great! Take care!