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|dw:1443498489098:dw|

is there a typo?
`The area of the circle is increasing at a constant rate^2/sec`

yep sorry about that " the area of the circle is increasing at a constant rate of 15pi in^2/sec

oh ok that makes more sense now

;P , alright so for the area of the square im getting (2r)^2 , not sure where to go on frem there

|dw:1443498822076:dw|
hopefully you see how the diameter d is equal to the side length of the square

yes the side length is 2r

A = (2r)^2 = 4r^2

if A = 4r^2, then what is dA/dt ?

8r dr/dt

yes

okay but we dont have dr/dt we only have da/dt of the circle

Circle
Ac = pi*r^2
dAc/dt = 2*pi*r*dr/dt
15pi = 2*pi*r*dr/dt

Rectangle
Ar = 4r^2
dAr/dt = 8r*dr/dt
try to connect dAc/dt and dAr/dt somehow

15/2r = dr/dt

I'm thinking to divide the two
so maybe
dAc/dt divided by dAr/dt

okay one sec let me process this

okay nvm i found an easier way

60 is correct

yep didn't see that , thanks for your help really appreciate it :D

no problem