Suppose you are using a system of units based on the centimeter (cm) for length, the gram (g) for mass, and the second (s) for time. The kinetic energy that an object has because of its motion is equal to half its mass times its speed squared, or KE=1/2mv2. In this system of units, what units would be used to express KE? g*cm2/s2 g*cm/s kg*cm2/s2 g*cm3/s

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Suppose you are using a system of units based on the centimeter (cm) for length, the gram (g) for mass, and the second (s) for time. The kinetic energy that an object has because of its motion is equal to half its mass times its speed squared, or KE=1/2mv2. In this system of units, what units would be used to express KE? g*cm2/s2 g*cm/s kg*cm2/s2 g*cm3/s

Physics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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m is mass v is velocity Mass would have to be in grams according to your question Cm would have to be your distance or length Time would have to be in seconds But velocity is distance (cm)/time (s) so units for velocity is cm/s
Show me your work. Dont tell me.
ok so half of grams time speed squared would be g/s^2
so A then?
Stop mentioning answers until you solved it please.
ok but Im sure is A now because it seems similar to what the problem is saying
grams times speed is \[g \times \frac{ m }{ s }\]
yes but the speed on the problem is squared
If you solve it algebraically, I can confirm your answer. Tell me which part you are lost in and I will help.
Yep that is logical, but it might not always be correct.
nvm Im not lost anymore, I got this, and thank you for your help :)
No problem! Good luck on the rest.
thank you :)

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