## InspectorJoe one year ago need help correcting my answers on two problems: (6,1) and (-20,35) also (60, 5) and (-20, 35)

1. jim_thompson5910

you'll need to post the full problem please

2. inspectorjoe

find out the distance between the pair of points. give an exact answer and where appropriate an approximation to there decimal place

3. jim_thompson5910

thanks

4. jim_thompson5910

you'll need to use the distance formula $\Large d = \sqrt{\left(x_{2}-x_{1}\right)^2+\left(y_{2}-y_{1}\right)^2}$

5. jim_thompson5910

for (6,1) and (-20,35) we see that x1 = 6 y1 = 1 x2 = -20 y2 = 35

6. inspectorjoe

yes i know but my answers are off trying to figure out why or how it should look since i can't seems to figure out why

7. jim_thompson5910

what answer did you get for the first one

8. inspectorjoe

yes I got that

9. inspectorjoe

the first one I got $D=\sqrt{2,500}$

10. inspectorjoe

the second i got $D=\sqrt{1492}$

11. jim_thompson5910

the first one is too big

12. jim_thompson5910

one sec

13. jim_thompson5910

For for (6,1) and (-20,35) $\Large d = \sqrt{\left(x_{2}-x_{1}\right)^2+\left(y_{2}-y_{1}\right)^2}$ $\Large d = \sqrt{\left(6-(-20)\right)^2+\left(1-35\right)^2}$ $\Large d = \sqrt{\left(6+20\right)^2+\left(1-35\right)^2}$ $\Large d = \sqrt{\left(26\right)^2+\left(-34\right)^2}$ $\Large d = \sqrt{676+1156}$ $\Large d = \sqrt{1832}$ Now you can simplify the radical to get... $\Large d = \sqrt{1832}$ $\Large d = \sqrt{4*458}$ $\Large d = \sqrt{4}*\sqrt{458}$ $\Large d = 2\sqrt{458}$

14. jim_thompson5910

hopefully you can see how I got all that

15. inspectorjoe

the book gives us an answer of $\sqrt{45,6.708}$

16. jim_thompson5910

something is odd about that format

17. jim_thompson5910

are you sure it says that?

18. inspectorjoe

yes

19. inspectorjoe

question though why do you go the opposite when replacing the formula with the problem. or does it matter. meaning you did X1 - X2 and not X2-X1