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- InspectorJoe

need help correcting my answers on two problems:
(6,1) and (-20,35)
also
(60, 5) and (-20, 35)

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- InspectorJoe

need help correcting my answers on two problems:
(6,1) and (-20,35)
also
(60, 5) and (-20, 35)

- katieb

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- jim_thompson5910

you'll need to post the full problem please

- InspectorJoe

find out the distance between the pair of points. give an exact answer and where appropriate an approximation to there decimal place

- jim_thompson5910

thanks

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- jim_thompson5910

you'll need to use the distance formula
\[\Large d = \sqrt{\left(x_{2}-x_{1}\right)^2+\left(y_{2}-y_{1}\right)^2}\]

- jim_thompson5910

for (6,1) and (-20,35) we see that
x1 = 6
y1 = 1
x2 = -20
y2 = 35

- InspectorJoe

yes i know but my answers are off trying to figure out why or how it should look since i can't seems to figure out why

- jim_thompson5910

what answer did you get for the first one

- InspectorJoe

yes I got that

- InspectorJoe

the first one I got
\[D=\sqrt{2,500}\]

- InspectorJoe

the second i got
\[D=\sqrt{1492}\]

- jim_thompson5910

the first one is too big

- jim_thompson5910

one sec

- jim_thompson5910

For for (6,1) and (-20,35)
\[\Large d = \sqrt{\left(x_{2}-x_{1}\right)^2+\left(y_{2}-y_{1}\right)^2}\]
\[\Large d = \sqrt{\left(6-(-20)\right)^2+\left(1-35\right)^2}\]
\[\Large d = \sqrt{\left(6+20\right)^2+\left(1-35\right)^2}\]
\[\Large d = \sqrt{\left(26\right)^2+\left(-34\right)^2}\]
\[\Large d = \sqrt{676+1156}\]
\[\Large d = \sqrt{1832}\]
Now you can simplify the radical to get...
\[\Large d = \sqrt{1832}\]
\[\Large d = \sqrt{4*458}\]
\[\Large d = \sqrt{4}*\sqrt{458}\]
\[\Large d = 2\sqrt{458}\]

- jim_thompson5910

hopefully you can see how I got all that

- InspectorJoe

the book gives us an answer of \[\sqrt{45,6.708}\]

- jim_thompson5910

something is odd about that format

- jim_thompson5910

are you sure it says that?

- InspectorJoe

yes

- InspectorJoe

question though why do you go the opposite when replacing the formula with the problem. or does it matter.
meaning you did
X1 - X2
and not
X2-X1

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