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InspectorJoe

  • one year ago

need help correcting my answers on two problems: (6,1) and (-20,35) also (60, 5) and (-20, 35)

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  1. jim_thompson5910
    • one year ago
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    you'll need to post the full problem please

  2. inspectorjoe
    • one year ago
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    find out the distance between the pair of points. give an exact answer and where appropriate an approximation to there decimal place

  3. jim_thompson5910
    • one year ago
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    thanks

  4. jim_thompson5910
    • one year ago
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    you'll need to use the distance formula \[\Large d = \sqrt{\left(x_{2}-x_{1}\right)^2+\left(y_{2}-y_{1}\right)^2}\]

  5. jim_thompson5910
    • one year ago
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    for (6,1) and (-20,35) we see that x1 = 6 y1 = 1 x2 = -20 y2 = 35

  6. inspectorjoe
    • one year ago
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    yes i know but my answers are off trying to figure out why or how it should look since i can't seems to figure out why

  7. jim_thompson5910
    • one year ago
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    what answer did you get for the first one

  8. inspectorjoe
    • one year ago
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    yes I got that

  9. inspectorjoe
    • one year ago
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    the first one I got \[D=\sqrt{2,500}\]

  10. inspectorjoe
    • one year ago
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    the second i got \[D=\sqrt{1492}\]

  11. jim_thompson5910
    • one year ago
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    the first one is too big

  12. jim_thompson5910
    • one year ago
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    one sec

  13. jim_thompson5910
    • one year ago
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    For for (6,1) and (-20,35) \[\Large d = \sqrt{\left(x_{2}-x_{1}\right)^2+\left(y_{2}-y_{1}\right)^2}\] \[\Large d = \sqrt{\left(6-(-20)\right)^2+\left(1-35\right)^2}\] \[\Large d = \sqrt{\left(6+20\right)^2+\left(1-35\right)^2}\] \[\Large d = \sqrt{\left(26\right)^2+\left(-34\right)^2}\] \[\Large d = \sqrt{676+1156}\] \[\Large d = \sqrt{1832}\] Now you can simplify the radical to get... \[\Large d = \sqrt{1832}\] \[\Large d = \sqrt{4*458}\] \[\Large d = \sqrt{4}*\sqrt{458}\] \[\Large d = 2\sqrt{458}\]

  14. jim_thompson5910
    • one year ago
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    hopefully you can see how I got all that

  15. inspectorjoe
    • one year ago
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    the book gives us an answer of \[\sqrt{45,6.708}\]

  16. jim_thompson5910
    • one year ago
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    something is odd about that format

  17. jim_thompson5910
    • one year ago
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    are you sure it says that?

  18. inspectorjoe
    • one year ago
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    yes

  19. inspectorjoe
    • one year ago
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    question though why do you go the opposite when replacing the formula with the problem. or does it matter. meaning you did X1 - X2 and not X2-X1

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