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anonymous
 one year ago
a driver of a car traveling at 15.0 m/s applies the breaks, causing a uniform acceleration of 2.0 m/s^2. how long does it take the car to accelerate to a final speed of 10.0 m/s?
i just need to know the delta x, delta time and vi and the vf please!!!
anonymous
 one year ago
a driver of a car traveling at 15.0 m/s applies the breaks, causing a uniform acceleration of 2.0 m/s^2. how long does it take the car to accelerate to a final speed of 10.0 m/s? i just need to know the delta x, delta time and vi and the vf please!!!

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0vi is initial velocity. It began at 15.0 m/s as you can see from your question. vf is final velocity. The driver is decelerating (slowing down) to 10 m/s.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Delta x is a change in position, so it would be the distance.

Abhisar
 one year ago
Best ResponseYou've already chosen the best response.1You can use V = U + at to find the time required.

Abhisar
 one year ago
Best ResponseYou've already chosen the best response.1V = Final velocity U = initial velocity a = retardation/deceleration t = time taken

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\Delta x=x _{f}x _{i}\] \[x _{f}=x _{0}+v _{i}t+\frac{ 1 }{ 2 }at^2\] \[x _{f}x _{i}=v _{i}t+\frac{ 1 }{ 2 }at^2\] \[\Delta x=v _{i}t+\frac{ 1 }{ 2 }at^2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do \[v _{f}=v _{i}+at\] first to get time first.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I am going to try an make sure that your understanding of this topic is clear; So someone is driving a car with a speed of 15 m/s. This is the velocity that the question starts with making it the 'initial' velocity. acceleration is a change in speed, if it is negative, the speed is going down, if not then the speed is increasing. So if someone is decelerating at a rate of 2m/s^2 then that means that every second, his speed is going down by 2m/s. Example: 15m/s is the 'initial' velocity, after one second the velocity will decrease by 2m/s which will give us 152=13m/s. Now we already know how slow the diver wants to go which is 10m/s from 15m/s. This means the driver wants to decrease his speed by 5m/s at a rate of 2m/s^2, so after 2 seconds he will have slowed down by 4m/s to give us 11m/s and after another half second he will have reached 10m/s which is his final velocity, and he took 2.5 seconds to do that. If you still can't do this problem 'without thinking' please tell me what you haven't understood.
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