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anonymous

  • one year ago

3. Solve the system by the substitution method. Show your work. 2y - x = 5 x2 + y2 - 25=0 ?

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  1. anonymous
    • one year ago
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    y(4y + y - 20) = 0 so, y = 0 or 4y+y-20 = 0 5y -20 = 0 y =45y-20=05(4)-20=00=0 x = 2y -5when y=4x = 8-5 =32y - x = 5x2 + y2- 25 = 02y - x = 5 2y - 5 = x so x = 2y - 5 (2y - 5)² + y² - 25 = 0 (2y - 5)(2y - 5) 4y² - 10y - 10y + 25 4y² - 20y + 25 4y² - 20y + 25 + y² - 25 = 0 4y² + y² - 20y = 0 4y² + y² - 20y = 0 y(4y + y - 20) = 0 y=0 x= -5 2y - x = 5 2(0) - x = 5, so x= -5) (-5,0) this wwas my answer

  2. anonymous
    • one year ago
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    my teacher said 3. Solve for x using equation 1 and then substitute this in the second equation. Once you simplify you will have a quadratic equation which you can factor and solve. Remember to factor out the GCF first.. The solutions should be written as ordered pairs (x1,y1) and (x2,y2).

  3. anonymous
    • one year ago
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    @Abhisar @Clalgee @dan815 @ganeshie8

  4. anonymous
    • one year ago
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    if my answer is correct what did she mean she only gave me two out of five points for thisw question

  5. anonymous
    • one year ago
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    @ShadowLegendX

  6. anonymous
    • one year ago
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    @nevermind_justschool

  7. anonymous
    • one year ago
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    @peachpi

  8. anonymous
    • one year ago
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    For one, you should have two solutions

  9. anonymous
    • one year ago
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    or did I miss it?

  10. anonymous
    • one year ago
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    somone sadi to use (3,4)

  11. anonymous
    • one year ago
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    \(2y - x = 5\) → \(x=2y-5\) \(x^2 + y^2 - 25=0\) \((2y-5)^2+y^2-25=0\) \(4y^2-20y+25+y^2-25=0\) \(5y^2-20y=0\) \(5y(y-4)=0\) \(y=0,~y=4\) Back substitute to find x

  12. anonymous
    • one year ago
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    ok I see. On this line you needed to solve for both y's y(4y + y - 20) = 0 You got \(y = 0\), but missed \(4y+y-20=0\)

  13. anonymous
    • one year ago
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    wait there were two y's

  14. anonymous
    • one year ago
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    yep. That's a quadratic equation so it has two solutions

  15. anonymous
    • one year ago
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    ohh so i nned solve for the second one right

  16. anonymous
    • one year ago
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    yes

  17. anonymous
    • one year ago
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    can you help me withthat im so sleepy but i needa get this done

  18. anonymous
    • one year ago
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    I already put it up there. It's 4

  19. anonymous
    • one year ago
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    ohh ik that thnx hahaha see my sleepiness is messing with my brain thnx again padre

  20. anonymous
    • one year ago
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    np

  21. anonymous
    • one year ago
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    how do i copy and paste that i cant seem to get it highlighted to copy it and its killing me lol

  22. anonymous
    • one year ago
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    help me one more time please @peachpi

  23. anonymous
    • one year ago
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    idk that happens a lot with chrome. try double clicking the whole thing then deleting what you don't want

  24. anonymous
    • one year ago
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    its mot working when i double click it it hightlights like 1 number

  25. anonymous
    • one year ago
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    maybe try another browser

  26. anonymous
    • one year ago
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    i got it highlighted but it wont let me coppy it

  27. anonymous
    • one year ago
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    is there another way you could write it for me or nah

  28. anonymous
    • one year ago
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    why can't you use what you had originally. It's right. Just add the line y = 4, x = 3 at the end

  29. anonymous
    • one year ago
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    ohh ok i thought i needed the whole thing sorry

  30. anonymous
    • one year ago
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    no, your stuff is good. you just missed one of the solutions, last step.

  31. anonymous
    • one year ago
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    ok thnx bro gn

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