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anonymous

  • one year ago

I need help with this graph please I am sending the file because I cannot send the graphs

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  1. anonymous
    • one year ago
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    here is my graph enclosed

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  2. anonymous
    • one year ago
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    I would appreciate any help I can get I truly do not understand this kind of math

  3. FireKat97
    • one year ago
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    a. For a graph to be a function, it must pass the vertical line test. The vertical line test is a test you do by drawing vertical lines through the graph and checking to see if, at any point, the line cuts the graph more than once, if it does cut the graph more than once, then the graph isn't a function Eg.|dw:1443505429946:dw|

  4. FireKat97
    • one year ago
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    |dw:1443505507001:dw|

  5. FireKat97
    • one year ago
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    b. The domain is the range of x co-ordinates on a graph so for eg.|dw:1443505650004:dw| the domain of this graph is -3 <= x <= 5

  6. FireKat97
    • one year ago
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    c. The range, describes all the y coordinates that make up a certain graph, so for e.g. |dw:1443505842409:dw| The range here would be -4 <= y <= 4

  7. anonymous
    • one year ago
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    you know your stuff really well. I have done that vretical line test about ten times and still felt confused.

  8. FireKat97
    • one year ago
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    with the vertical line test, if its failed at any point, the graph is not considered a function, even if it fails at one point alone

  9. FireKat97
    • one year ago
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    Just imagine cutting the graph at numerous spots, and if at any spot, its cut more than once, its no loner a function, its just a matter of practice really

  10. anonymous
    • one year ago
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    I sure done a lot of practicing and got nowhere it felt like

  11. FireKat97
    • one year ago
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    one sec

  12. FireKat97
    • one year ago
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    https://www.youtube.com/watch?v=jzNNUuol26Q This may help

  13. anonymous
    • one year ago
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    thank you

  14. FireKat97
    • one year ago
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    I always find youtube videos helpful, whenever I get stuck on a new concept so worth a shot...

  15. FireKat97
    • one year ago
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    problem :)

  16. FireKat97
    • one year ago
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    No*

  17. anonymous
    • one year ago
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    I am so sorry but i have to go to bed I spent all day at the drs. and am feeling it. But thank you so much for helping me and I do appreciate it.

  18. anonymous
    • one year ago
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    and I will watch the video tomorrow

  19. FireKat97
    • one year ago
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    okay no problem, just tag me later if you're still confused

  20. anonymous
    • one year ago
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    okay how do I tag you

  21. anonymous
    • one year ago
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    I am new on here

  22. FireKat97
    • one year ago
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    Just do @Firekat97

  23. anonymous
    • one year ago
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    okay I will tag you tomorrow thanks

  24. FireKat97
    • one year ago
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    no problem :)

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