## jojokiw3 one year ago Can someone tell me if my answer to this is correct?

1. jojokiw3

$\sum_{n=1}^{3}(n^2-2) = 8$

2. FireKat97

Yup thats correct

3. whpalmer4

$\sum_{n=1}^{3}(n^2-2)=(1^2-2) + (2^2-2)+(3^2-2) = (1-2)+(4-2)+(9-2)$$= -1+2+7=8\checkmark$

4. jojokiw3

Thanks! I just wanted to make sure I remember the method correctly.

5. whpalmer4

Whether you did or not, you got the correct answer :-)