anonymous one year ago Bayes Probability Question

1. anonymous

2. anonymous

We are given $P(C|Q _{G}) = 0.72$ $P(C|Q _{OK}) = 0.40$ $P(C|Q _{B}) =0.00$ Using Bayes' Formula we know that $P(C|Q _{G}) = \frac{ P(C ∩ Q _{G}) }{ P(Q _{G}) }= 0.72$ $P(C|Q _{G}) = \frac{ P(C ∩ Q _{OK}) }{ P(Q _{OK}) }= 0.40$ $P(C|Q _{G}) = \frac{ P(C ∩ Q _{B}) }{ P(Q _{B}) }= 0.00$

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