anonymous
  • anonymous
help I suck at math
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
ParthKohli
  • ParthKohli
are you asking for psychiatric help
anonymous
  • anonymous
I could be
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anonymous
  • anonymous
fashoo thats 7/2

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anonymous
  • anonymous
thank you!!
abb0t
  • abb0t
Answer is 3.5
whpalmer4
  • whpalmer4
Here, maybe instead of giving you the answer, someone could show you how to get it yourself and actually help you in a productive way... \[2x-4 = \frac{4x-5}{3}\] Start by multiplying both sides by \(3\) to eliminate the fraction. \[3(2x-4) = 3*\frac{4x-5}{3}\]\[6x-12 = \cancel{3}\frac{4x-5}{\cancel{3}}\] \[6x-12 = 4x-5\]Add \(12\) to both sides \[6x-12+12 = 4x-5+12\]\[6x = 4x+7\]Now subtract \(4x\) from both sides \[6x-4x = 4x-4x+7\]\[2x=7\]Finally, divide both sides by \(2\) to give you \(x\) alone on one side, and its value on the other: \[\frac{2x}{2} = \frac{7}{2}\]\[x=\frac{7}2\] General idea is you can do anything to an equation as long as you do the same thing to both sides. Just keep doing stuff to simplify it until you have your variable alone on one side.
anonymous
  • anonymous
Thank you for explaining it, I understand it much better now! @whpalmer4

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