The length of a rectangle is four times its width. If the area of the rectangle is 100 ft2 , find its perimeter.

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The length of a rectangle is four times its width. If the area of the rectangle is 100 ft2 , find its perimeter.

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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l=4w 100=4w*w 100=4(w)square w=5 perimeter=2(l+w) p=2(25) p=50
Area = width* length if the unknown width is "x" then the length is "4x" area = 100 = 4x *x \[4x ^{2} =100\] \[x ^{2} = 25\] \[x =5\] So the width is 5 and the length is 4*5 = 20 Perimeter = length *2 +width *2 permiter = (20 *2 ) + (5*2) = 40 +10 = 50

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