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anonymous

  • one year ago

Find x in this 45°-45°-90° triangle.

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    the diagonal is the side times \(\sqrt2\) \that means \[x\times \sqrt2=12\] making \[x=\frac{12}{\sqrt2}\]

  3. anonymous
    • one year ago
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    you probably have to rationalize the denominator

  4. anonymous
    • one year ago
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    do you know how to do that?

  5. anonymous
    • one year ago
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    I don't. this is from a year ago and my school is making me do it again. if you dont mind could you go step by step for me?

  6. anonymous
    • one year ago
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    sure

  7. anonymous
    • one year ago
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    to get the radical out of the denominator in \(\frac{12}{\sqrt2}\) multiply by \(\frac{\sqrt2}{\sqrt2}\) i.e. \[\frac{12}{\sqrt2}\times \frac{\sqrt2}{\sqrt2}\]

  8. anonymous
    • one year ago
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    you get \[\frac{12\sqrt2}{2}\] then reduce the fraction

  9. anonymous
    • one year ago
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    do i solve 12 square root 2? or leave it alone?

  10. anonymous
    • one year ago
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    you do not "solve" anything, you reduce the fraction

  11. anonymous
    • one year ago
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    divide 12 by 2 in other words

  12. anonymous
    • one year ago
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    6 square root 2?

  13. anonymous
    • one year ago
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    yes

  14. anonymous
    • one year ago
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    you notice that should fit nicely in to your template

  15. anonymous
    • one year ago
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    Thank you so much

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spraguer (Moderator)
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