A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
The velocity function, in feet per second, is given for a particle moving along a straight line.
v(t) = t2 − t − 132, 1 ≤ t ≤ 15
Find the total distance that the particle travels over the given interval
anonymous
 one year ago
The velocity function, in feet per second, is given for a particle moving along a straight line. v(t) = t2 − t − 132, 1 ≤ t ≤ 15 Find the total distance that the particle travels over the given interval

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Integrate v(t), but when you solve v(t) = 0 and you'll see there's a root at t = 12, so break up the integral. \[\left \int\limits_{1}^{12}v(t)~dt \right+\left \int\limits_{12}^{15}v(t)~dt \right\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got 3084.667 why is the not right

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't know what you did. can you put up your work?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\int\limits \frac{ t^{3} }{ 3 }\frac{ t^{2} }{ 2 }+132t\] thats what I used for my integral then I plugged in 1 & 12, then subtracted the 1 value from the 12 value. Then I plugged in 15 and subtracted the 12 value from that & then added the two subtractions

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\left \frac{ t^3 }{ 3 }\frac{ t^2 }{ 2 }132t \right_1^{12}=\left 1080(\frac{ 793 }{ 6 }) \right=\frac{ 5687 }{ 6 }\] \[\left \frac{ t^3 }{ 3 }\frac{ t^2 }{ 2 }132t \right_{12}^{15}=\left \frac{ 1935 }{ 2 }(1080) \right=\frac{ 225 }{ 2 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0add them together to get 381/3 ≈ 1060.3 ft

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but 12 is the zero so you would be adding that integral

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes, you want to add the two area to get the total distance traveleddw:1443626627072:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so that isn't the right answer, it's also telling me that it isn't right haha

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0try it without the absolute value signs. 5687/6 + 225/2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but then that would be the dispacement

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i literally got the same thing.. 1060.33 i don't know why it isn't right
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.