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anonymous
 one year ago
A student is solving the equation 81^x – 1 = 3^x + 2
Step 1: 81x – 1 =3x + 2
Step 2: (34)x – 1 = 3x + 2
Step 3: 34x – 4 = 3x + 2
Which is the next step?
x – 1 = x + 2
4x – 4 = x + 2
4x – 4 = –(x + 2)
4(x – 1) = 3(x + 2)
anonymous
 one year ago
A student is solving the equation 81^x – 1 = 3^x + 2 Step 1: 81x – 1 =3x + 2 Step 2: (34)x – 1 = 3x + 2 Step 3: 34x – 4 = 3x + 2 Which is the next step? x – 1 = x + 2 4x – 4 = x + 2 4x – 4 = –(x + 2) 4(x – 1) = 3(x + 2)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0OK. I'm assuming that the exponent on the LHS is (x1). and the exponent on the RHS is x +2. So, ((3)^4)^(x1) = 3^(x+2) Now you have both sides to the same base so you can equate the exponents 4x4 = x+2. Adding 4 to both sides and subtracting x from both sides this gives you 3x = 6 or x = 2 > and this checks.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.081^x 1 = 3^x + 2 OR 3^4x = 3^(x + 3) whence 4x = x + 3 OR x = 1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so would it be the 1st one

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[3^{4x4}=3^{x+2}\iff 4x4=x+2\]
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