some.random.cool.kid
  • some.random.cool.kid
Solve the system y equals negative x squared, y equals x minus two.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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some.random.cool.kid
  • some.random.cool.kid
@ganeshie8 @Zarkon @zzr0ck3r @Nnesha
some.random.cool.kid
  • some.random.cool.kid
@undeadknight26 @peachpi
some.random.cool.kid
  • some.random.cool.kid
@ParthKohli

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Nnesha
  • Nnesha
\[\huge\rm y=-x^2\]\[\huge\rm \color{ReD}{y}=x-2\] substitute red y for first equation
Nnesha
  • Nnesha
|dw:1443539180290:dw| and then solve the quadratic equation
some.random.cool.kid
  • some.random.cool.kid
ok
Nnesha
  • Nnesha
let me know what u get after that
some.random.cool.kid
  • some.random.cool.kid
not sure..
some.random.cool.kid
  • some.random.cool.kid
is it now -x^2 = x -2?
Nnesha
  • Nnesha
right
some.random.cool.kid
  • some.random.cool.kid
so what do i do next im confused?
Nnesha
  • Nnesha
set it equal to zero move -x^2 to the right side then solve for x
some.random.cool.kid
  • some.random.cool.kid
ok
some.random.cool.kid
  • some.random.cool.kid
"-x^2" = x -2 so im moving whats in quotes to the right side of the equal sign right? after that do multiply or do some division of any sort to solve for x?
Nnesha
  • Nnesha
yes right move -x^2 to the right side then u will get the quadratic equation and i'm pretty sure you r familiar with the quadratic equations we solved 3 q yesterday
some.random.cool.kid
  • some.random.cool.kid
yeah ok
some.random.cool.kid
  • some.random.cool.kid
so now it should look like this right = x -2 -x^2 im not sure what happens to the equal thoough and i believe that the quad equation to solve this is- "ax2 + bx + c"
Nnesha
  • Nnesha
|dw:1443541053008:dw| when u move number/variable from one side to ohter sign would change
Nnesha
  • Nnesha
how would you cancel out -x^2 from left side ?

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