Solve the system y equals negative x squared, y equals x minus two.

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Solve the system y equals negative x squared, y equals x minus two.

Mathematics
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\[\huge\rm y=-x^2\]\[\huge\rm \color{ReD}{y}=x-2\] substitute red y for first equation
|dw:1443539180290:dw| and then solve the quadratic equation
ok
let me know what u get after that
not sure..
is it now -x^2 = x -2?
right
so what do i do next im confused?
set it equal to zero move -x^2 to the right side then solve for x
ok
"-x^2" = x -2 so im moving whats in quotes to the right side of the equal sign right? after that do multiply or do some division of any sort to solve for x?
yes right move -x^2 to the right side then u will get the quadratic equation and i'm pretty sure you r familiar with the quadratic equations we solved 3 q yesterday
yeah ok
so now it should look like this right = x -2 -x^2 im not sure what happens to the equal thoough and i believe that the quad equation to solve this is- "ax2 + bx + c"
|dw:1443541053008:dw| when u move number/variable from one side to ohter sign would change
how would you cancel out -x^2 from left side ?

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