## some.random.cool.kid one year ago Solve the system y equals negative x squared, y equals x minus two.

1. some.random.cool.kid

@ganeshie8 @Zarkon @zzr0ck3r @Nnesha

2. some.random.cool.kid

3. some.random.cool.kid

@ParthKohli

4. Nnesha

$\huge\rm y=-x^2$$\huge\rm \color{ReD}{y}=x-2$ substitute red y for first equation

5. Nnesha

|dw:1443539180290:dw| and then solve the quadratic equation

6. some.random.cool.kid

ok

7. Nnesha

let me know what u get after that

8. some.random.cool.kid

not sure..

9. some.random.cool.kid

is it now -x^2 = x -2?

10. Nnesha

right

11. some.random.cool.kid

so what do i do next im confused?

12. Nnesha

set it equal to zero move -x^2 to the right side then solve for x

13. some.random.cool.kid

ok

14. some.random.cool.kid

"-x^2" = x -2 so im moving whats in quotes to the right side of the equal sign right? after that do multiply or do some division of any sort to solve for x?

15. Nnesha

yes right move -x^2 to the right side then u will get the quadratic equation and i'm pretty sure you r familiar with the quadratic equations we solved 3 q yesterday

16. some.random.cool.kid

yeah ok

17. some.random.cool.kid

so now it should look like this right = x -2 -x^2 im not sure what happens to the equal thoough and i believe that the quad equation to solve this is- "ax2 + bx + c"

18. Nnesha

|dw:1443541053008:dw| when u move number/variable from one side to ohter sign would change

19. Nnesha

how would you cancel out -x^2 from left side ?