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anonymous

  • one year ago

Will Fan and Medal!!! Just need someone to check these for me!!!!

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    @Nnesha @pooja195 @ganeshie8 can any of you help me please

  3. whpalmer4
    • one year ago
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    No, the first one is not correct, didn't check the rest.

  4. anonymous
    • one year ago
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    ok then would the first one be a?

  5. whpalmer4
    • one year ago
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    One check you can do yourself for checking inverse functions is to plot a few points of the original function and a few of the inverse. The inverse function will be an exact replica of the original reflected across the line \(y = x\) (just a line extending up and to the right at a \(45^\circ\) angle). I have plotted your answer here so you can see that it is not correct:

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  6. whpalmer4
    • one year ago
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    Here's what it would look like if correct:

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  7. whpalmer4
    • one year ago
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    No, (a) is not correct either. Can you show me how you are doing this?

  8. anonymous
    • one year ago
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    ok what did u use to get that? that can help me

  9. anonymous
    • one year ago
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    my teacher just told us that you would need to make everything opposite?

  10. whpalmer4
    • one year ago
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    Oh, it's an expensive program called Mathematica. There are undoubtedly many cheaper or free options, this just happens to be the one I have at hand. You could also use graph paper and pencil :-) Uh, that's probably not exactly how they put it... Let's say you want to find the inverse of \[f(x)=3x+2\]First, replace \(f(x)\) with \(y\): \[y = 3x+2\]now switch the two variables. anywhere you see \(y\), you put \(x\) and vice versa. \[x = 3y+2\] now solve that for \(y\) and you have your inverse function \[x-2=3y\]\[y = \frac{x-2}{3}\]

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  11. anonymous
    • one year ago
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    soo i dont really know what to do she not a very good teacher

  12. anonymous
    • one year ago
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    wow ok i understand now thanks can u check the rest imma try to solve it real quick

  13. whpalmer4
    • one year ago
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    ok, I'll the check the others and you do that one

  14. anonymous
    • one year ago
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    would it be umm d?

  15. anonymous
    • one year ago
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    1+x/4=y is what i got but it can also be the same thing as d right?

  16. anonymous
    • one year ago
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    |dw:1443542618922:dw|

  17. whpalmer4
    • one year ago
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    ah, yes, that's better. you need to write that as \[(1+x)/4 = y\]if you are going to write it all on one line like that

  18. whpalmer4
    • one year ago
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    by the rules of operator precedence, \[1+x/4 = y\] is the same as\[1 + \frac{x}{4} = y\]

  19. whpalmer4
    • one year ago
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    So yes, (d) is the correct answer for the first part. Unfortunately, you probably realize that you did 2 of the others incorrectly...but got the 3rd one right.

  20. whpalmer4
    • one year ago
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    (to be clear, 3rd one is referring to Question #3)

  21. anonymous
    • one year ago
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    yeah i realized that can i solve them and u check them for me real quick? yeah i know what u meant

  22. anonymous
    • one year ago
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    #1. D #2. idk how to do that one? #3. D #4. C Are they correct now and can you help me on question 2?

  23. anonymous
    • one year ago
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    @whpalmer4

  24. whpalmer4
    • one year ago
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    Ok, for 2, we have to first find the inverse function, then evaluate it at \(x=9\) What is the inverse function of \(y = 6x-3\)

  25. whpalmer4
    • one year ago
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    sorry, I looked too quickly at your answer for #3, that's not correct...but we'll work through it and get the right one.

  26. whpalmer4
    • one year ago
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    @Zbratz7 you home?

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