Linear algebra help dealing with the equation of a plane....please see attachment

- chrisplusian

Linear algebra help dealing with the equation of a plane....please see attachment

- Stacey Warren - Expert brainly.com

Hey! We 've verified this expert answer for you, click below to unlock the details :)

- jamiebookeater

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

- chrisplusian

##### 1 Attachment

- chrisplusian

I need help with 1.12, I have tried the problem twice and no luck proving it

- dan815

which part do u need help with the cartesian equation or the proof

Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

- anonymous

the first part of the question is simple getting you familiar with transforming a set of parametric equations into a cartesian equation

- anonymous

perhaps reading your notes on this will jog your memory

- chrisplusian

Bout to upload what I did give me just a second

- chrisplusian

@dan815 I Know if I can get both of these planes into Cartesian equations I can show that the normal vector is a scalar multiple of the other and that will prove the planes are parallel. Then showing any point on both planes is the same will prove they are the same plane. The problem is I can't get the Cartesian equations in a way that shows the normal vectors are the same. If the normal vectors are not the same then they can't be the same plane

- chrisplusian

@chris00 thanks for the tip about reading my notes, that never occurred to me

- chrisplusian

##### 1 Attachment

- dan815

ah okay thats quite a bit of work

- chrisplusian

Is there an easier way?

- dan815

the point 1,1,1 should satisfy both equations correct?

- chrisplusian

Well yes, but it doesn't prove they are the same plane

- dan815

we will use that fact to prove it

- chrisplusian

Ok

- dan815

all we need are 2 things to be satisfied, both of them should have the same normal direction, and one point that is common,

- chrisplusian

agreed

- dan815

from the 2 equations you derived, i can say there has been a mistake as both of the normal lines are not equal

- chrisplusian

That is what I thought but i can't see where. I actually did it twice and got the same exact thing so I figured there must be a mistake in the logic I used to derive the equations rather than a mistake in arithmetic or algebra

- dan815

http://prntscr.com/8m15ta

- chrisplusian

Because I came up with the same two equations both times

- dan815

okay can u compute that, and show mw the 2 normal vectors you get again

- chrisplusian

The way you annotated it?

- chrisplusian

I get what your saying, and it makes perfect sense, but this professor wants us to show the Cartesian equations and then use the normal vectors in those equations to show they are parallel normal vectors.

- chrisplusian

And this problem follows along those lines, because the first step is to find the Cartesian equation of the first line.

- dan815

yep u can get the cartesian equations this way too

- dan815

suppose you have a normal vector
then your plane equations is
ax+by+cz=d
now you can solve for d, by plugging in one of your known points
for example the (1,1,1)

- dan815

you repeat the same process for equation 2

- chrisplusian

Ah, I see where your going and I didn't think of it that way. Let me try that way and see if I come up with an answer. Thank you

- dan815

then you will see that a point in equation 1 exists in equation 2 as well, then these 2 places must coincide, because any 2 planes with the same normal vector direction will be parralel and can* only have a similiar point if they are in fact coincident

- anonymous

so you can check your answers,
the first parametric eq has carteisian form:
\[3x _{1}-4x _{2}+2_{3}=1\]
second one has cartesian form:
\[-24x _{1}+32x _{2}-16x _{3}=-8\]
now if u divide the second equation by -8 on both sides, you will see it is simply the cartesian equation of the first plane

- anonymous

but as @dan815 said, its important to find the normal vector in these questions

- anonymous

|dw:1443579442336:dw|

Looking for something else?

Not the answer you are looking for? Search for more explanations.