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anonymous
 one year ago
Linear algebra help dealing with the equation of a plane....please see attachment
anonymous
 one year ago
Linear algebra help dealing with the equation of a plane....please see attachment

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I need help with 1.12, I have tried the problem twice and no luck proving it

dan815
 one year ago
Best ResponseYou've already chosen the best response.2which part do u need help with the cartesian equation or the proof

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the first part of the question is simple getting you familiar with transforming a set of parametric equations into a cartesian equation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0perhaps reading your notes on this will jog your memory

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Bout to upload what I did give me just a second

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@dan815 I Know if I can get both of these planes into Cartesian equations I can show that the normal vector is a scalar multiple of the other and that will prove the planes are parallel. Then showing any point on both planes is the same will prove they are the same plane. The problem is I can't get the Cartesian equations in a way that shows the normal vectors are the same. If the normal vectors are not the same then they can't be the same plane

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@chris00 thanks for the tip about reading my notes, that never occurred to me

dan815
 one year ago
Best ResponseYou've already chosen the best response.2ah okay thats quite a bit of work

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is there an easier way?

dan815
 one year ago
Best ResponseYou've already chosen the best response.2the point 1,1,1 should satisfy both equations correct?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well yes, but it doesn't prove they are the same plane

dan815
 one year ago
Best ResponseYou've already chosen the best response.2we will use that fact to prove it

dan815
 one year ago
Best ResponseYou've already chosen the best response.2all we need are 2 things to be satisfied, both of them should have the same normal direction, and one point that is common,

dan815
 one year ago
Best ResponseYou've already chosen the best response.2from the 2 equations you derived, i can say there has been a mistake as both of the normal lines are not equal

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That is what I thought but i can't see where. I actually did it twice and got the same exact thing so I figured there must be a mistake in the logic I used to derive the equations rather than a mistake in arithmetic or algebra

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Because I came up with the same two equations both times

dan815
 one year ago
Best ResponseYou've already chosen the best response.2okay can u compute that, and show mw the 2 normal vectors you get again

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The way you annotated it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I get what your saying, and it makes perfect sense, but this professor wants us to show the Cartesian equations and then use the normal vectors in those equations to show they are parallel normal vectors.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And this problem follows along those lines, because the first step is to find the Cartesian equation of the first line.

dan815
 one year ago
Best ResponseYou've already chosen the best response.2yep u can get the cartesian equations this way too

dan815
 one year ago
Best ResponseYou've already chosen the best response.2suppose you have a normal vector <a,b,c> then your plane equations is ax+by+cz=d now you can solve for d, by plugging in one of your known points for example the (1,1,1)

dan815
 one year ago
Best ResponseYou've already chosen the best response.2you repeat the same process for equation 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ah, I see where your going and I didn't think of it that way. Let me try that way and see if I come up with an answer. Thank you

dan815
 one year ago
Best ResponseYou've already chosen the best response.2then you will see that a point in equation 1 exists in equation 2 as well, then these 2 places must coincide, because any 2 planes with the same normal vector direction will be parralel and can* only have a similiar point if they are in fact coincident

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so you can check your answers, the first parametric eq has carteisian form: \[3x _{1}4x _{2}+2_{3}=1\] second one has cartesian form: \[24x _{1}+32x _{2}16x _{3}=8\] now if u divide the second equation by 8 on both sides, you will see it is simply the cartesian equation of the first plane

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but as @dan815 said, its important to find the normal vector in these questions

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443579442336:dw
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