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anonymous
 one year ago
Evaluate the given binomial coefficient (109/3)
anonymous
 one year ago
Evaluate the given binomial coefficient (109/3)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have no idea how to do these problems.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{109\times 108\times 107}{3\times 2}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0else cheat http://www.wolframalpha.com/input/?i=109+choose+3

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How does one know which steps to follow to do this problem. Just to confirm, the answer would be the resulting number of that fraction?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes that is the result

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\binom{109}{3}=\frac{\overbrace{109\times 108\times 107}^{\text {three terms}}}{3!}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So we know to go back three numbers (109, 108, 107) because it's over 3?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Why do we multiply 3 by 2?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the denominator is \(3!=3\times 2\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0as another example \[\binom{10}{4}=\frac{10\times 9\times 8\times 7}{4\times 3\times 2}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If the problem were, for instance (50/7), would it be (50x49x48x47x46x45x44/7x6x5x4x3x2)?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it is a whole number in each case, so to compute, cancel first multiply last

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And (7/7) would be (7x6x5x4x3x2x1/7x6x5x4x3x2)? Basically I just want to confirm that the denominator just always counts down to 2?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes, some people write a 1 there too, but that is silly because multiplying by one is like doing nothing

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0like they might write \(4!=4\times 3\times 2\times1\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Gotcha. So the "denominator" will always count down to 2, and the "numerator" will count down the number of the denominator?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0doesn't count town to the number in the bottom counts down that many terms (like in the example you wrote)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah i guess what you said is right if i interpret it correctly there is also a formula, but i wouldn't use it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah that's what I meant (the number of terms, not all the way down to that number). Thank you very much for explaining this all so clearly!
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