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Solve the following system of equations. 3x +1/4y =-3/4 -1/2x+1/3y=8

Mathematics
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are you sure you typed out those equations correctly? they look somewhat odd to me
ok, much better. we can start by multiplying the second equation by 6

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Other answers:

-3x+2y=48
good, now we have: 3x + (1/4)y = (-3/4) -3x + 2y = 48 now add the two equations together
x+2.25y=47.25
don't think I'm supposed to have decimals
almost 3x - 3x = ?
I know this one :)
x
nope, not quite hint: 3 - 3 = 0 3x - 3x = ?
0x
There is no such thing as 0x That would be just 0...
good, and 0x = 0 because 0 times anything is 0 so now we have: 2.25y = 47.25 y = ?
21
2.25y is saying 2.25 times y. Negate that by dividing. Divide both sides by 2.25
i did that
y= 21
what about solving for X
ok, now we know that y = 21 we can solve for x by plugging in y = 21 back into one of the other equations
for both equations
-(1/2)x + (1/3)y = 8 -(1/2)x + (1/3)21 = 8 -(1/2)x + 7 = 8 x = ?
we only need to plug in y = 21 into one of the equations, since both will give us the same x value
.5
1/2
nope, not quite (-1/2)x + 7 = 8 subtract 7 from each side to get (-1/2)x = 1 x = ?
-.5
nope, check your math again
1/(-1/2) = ?
-2
good, so x = -2 and y = 21
thanks!

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