## anonymous one year ago A water balloon slingshot launches its projectiles essentially from ground level at a speed of 25.5 m/s . (You can ignore air resistance.) A: At what angle should the slingshot be aimed to achieve its maximum range? B: If shot at the angle you calculated in Part A, how far will a water balloon travel horizontally? C: For how long will the balloon be in the air?

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1. IrishBoy123

the formulae for range and flight time for a given launch from ground level at angle $$\theta$$ are $R = \frac{v^2 \sin 2 \theta} {g}$ and $T = \frac{2 v \sin \theta} {g}$ these follow from the equations of motion and the parabolic/symmetric shape of flight without air resiatance you can see that you will max out on range at $$\theta = 45^o$$ this covers the ground nicely https://en.wikipedia.org/wiki/Range_of_a_projectile and is the source of the equations i shared