• anonymous
A water balloon slingshot launches its projectiles essentially from ground level at a speed of 25.5 m/s . (You can ignore air resistance.) A: At what angle should the slingshot be aimed to achieve its maximum range? B: If shot at the angle you calculated in Part A, how far will a water balloon travel horizontally? C: For how long will the balloon be in the air?
  • Stacey Warren - Expert
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  • katieb
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  • IrishBoy123
the formulae for range and flight time for a given launch from ground level at angle \(\theta \) are \[ R = \frac{v^2 \sin 2 \theta} {g} \] and \[ T = \frac{2 v \sin \theta} {g} \] these follow from the equations of motion and the parabolic/symmetric shape of flight without air resiatance you can see that you will max out on range at \(\theta = 45^o\) this covers the ground nicely and is the source of the equations i shared

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