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MTALHAHASSAN2
 one year ago
Differentiate each function. Do not expand an expression before differentiating.
a)f(x)=(2x+3)^4
MTALHAHASSAN2
 one year ago
Differentiate each function. Do not expand an expression before differentiating. a)f(x)=(2x+3)^4

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MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.1is it be like that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443580871976:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0where u(x)=2x+3 and n=4

MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.1oh ok f(x)= 4(2x+3)^3 (2) = 8(2x+3)^3

MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.1g(x)=(x^24)^3 =3(x^24)^2 =6x(x^24)^2 For this question Is it be like this!!

dan815
 one year ago
Best ResponseYou've already chosen the best response.0ayeee what tower is that in the back, lol why this place look so familiar!

MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.1lol its nagara falls!!!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0nah clearly that looks like the sydney harbour bridge

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes you are right @MTALHAHASSAN2 with the other question

Zarkon
 one year ago
Best ResponseYou've already chosen the best response.0you should not write g(x)=(x^24)^3 =3(x^24)^2 =6x(x^24)^2 as none of those are equal to each other

MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.1how about this one: f(x)= (pie^2x^2)3

MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.13(pie^2x^2)^2 (2piex)

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0\[\large\rm f(x)= (\pi^2x^2)^3\]Your first step looks good, applying power rule.\[\large\rm f'(x)= 3(\pi^2x^2)^2\color{royalblue}{(\pi^2x^2)'}\]But you also need chain rule.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0Derivative of x^2 is not x. And derivative of pi^2 is not 2pi.

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.02pi is just a number. It's a fancy looking constant. Remember how to differentiate a constant? \(\large\rm \frac{d}{dx}3=?\)

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0pi^2 is just a number* blah typo :)

MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.1then is it be 6(pie^2x^2)^2

MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.1@zepdrix is it right??

MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.1but at the back of the book they have 6 instead of 6

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0oh sorry i ran off for a sec >.<

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0\[\large\rm f'(x)= 3(\pi^2x^2)^2\color{royalblue}{(\pi^2x^2)'}\]\[\large\rm f'(x)= 3(\pi^2x^2)^2\color{orangered}{(02x)}\]Ya, don't forget about the negative in front of the x^2

zepdrix
 one year ago
Best ResponseYou've already chosen the best response.0\[\large\rm f'(x)= 3(\pi^2x^2)^2(2x)\]\[\large\rm f'(x)= 6x(\pi^2x^2)^2\]Understand why there is a negative? :o

MTALHAHASSAN2
 one year ago
Best ResponseYou've already chosen the best response.1yeah got you and thnx a lot
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