MTALHAHASSAN2
  • MTALHAHASSAN2
Differentiate each function. Do not expand an expression before differentiating. a)f(x)=(2x+3)^4
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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MTALHAHASSAN2
  • MTALHAHASSAN2
f(x)=4(2x+3)^3
MTALHAHASSAN2
  • MTALHAHASSAN2
is it be like that
LynFran
  • LynFran
use chain rule

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More answers

anonymous
  • anonymous
|dw:1443580871976:dw|
anonymous
  • anonymous
where u(x)=2x+3 and n=4
MTALHAHASSAN2
  • MTALHAHASSAN2
oh ok f(x)= 4(2x+3)^3 (2) = 8(2x+3)^3
anonymous
  • anonymous
good work
MTALHAHASSAN2
  • MTALHAHASSAN2
thnx
MTALHAHASSAN2
  • MTALHAHASSAN2
g(x)=(x^2-4)^3 =3(x^2-4)^2 =6x(x^2-4)^2 For this question Is it be like this!!
dan815
  • dan815
ayeee what tower is that in the back, lol why this place look so familiar!
MTALHAHASSAN2
  • MTALHAHASSAN2
lol its nagara falls!!!
dan815
  • dan815
hahahaha
dan815
  • dan815
thats skylone right
anonymous
  • anonymous
nah clearly that looks like the sydney harbour bridge
dan815
  • dan815
lmao pls xD
anonymous
  • anonymous
yes you are right @MTALHAHASSAN2 with the other question
MTALHAHASSAN2
  • MTALHAHASSAN2
ok thnx again
Zarkon
  • Zarkon
you should not write g(x)=(x^2-4)^3 =3(x^2-4)^2 =6x(x^2-4)^2 as none of those are equal to each other
MTALHAHASSAN2
  • MTALHAHASSAN2
how about this one: f(x)= (pie^2-x^2)3
MTALHAHASSAN2
  • MTALHAHASSAN2
3(pie^2-x^2)2
MTALHAHASSAN2
  • MTALHAHASSAN2
3(pie^2-x^2)^2 (2pie-x)
zepdrix
  • zepdrix
\[\large\rm f(x)= (\pi^2-x^2)^3\]Your first step looks good, applying power rule.\[\large\rm f'(x)= 3(\pi^2-x^2)^2\color{royalblue}{(\pi^2-x^2)'}\]But you also need chain rule.
zepdrix
  • zepdrix
Ah very close!
zepdrix
  • zepdrix
Derivative of x^2 is not x. And derivative of pi^2 is not 2pi.
MTALHAHASSAN2
  • MTALHAHASSAN2
i know its 2x
zepdrix
  • zepdrix
2pi is just a number. It's a fancy looking constant. Remember how to differentiate a constant? \(\large\rm \frac{d}{dx}3=?\)
zepdrix
  • zepdrix
pi^2 is just a number* blah typo :)
MTALHAHASSAN2
  • MTALHAHASSAN2
then is it be 6(pie^2-x^2)^2
MTALHAHASSAN2
  • MTALHAHASSAN2
@zepdrix is it right??
MTALHAHASSAN2
  • MTALHAHASSAN2
but at the back of the book they have -6 instead of 6
zepdrix
  • zepdrix
oh sorry i ran off for a sec >.<
MTALHAHASSAN2
  • MTALHAHASSAN2
oh ok np
zepdrix
  • zepdrix
\[\large\rm f'(x)= 3(\pi^2-x^2)^2\color{royalblue}{(\pi^2-x^2)'}\]\[\large\rm f'(x)= 3(\pi^2-x^2)^2\color{orangered}{(0-2x)}\]Ya, don't forget about the negative in front of the x^2
zepdrix
  • zepdrix
\[\large\rm f'(x)= 3(\pi^2-x^2)^2(-2x)\]\[\large\rm f'(x)= -6x(\pi^2-x^2)^2\]Understand why there is a negative? :o
MTALHAHASSAN2
  • MTALHAHASSAN2
yeah got you and thnx a lot

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