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MTALHAHASSAN2

  • one year ago

Differentiate each function. Do not expand an expression before differentiating. a) y=sqrt x^2-3

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  1. frank0520
    • one year ago
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    use the chain rule \[\frac{ d }{ dx }(\sqrt{x^2 -3})\]

  2. MTALHAHASSAN2
    • one year ago
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    ok so then it be like =(x-3^1/2) if we finish the sqrt root

  3. MTALHAHASSAN2
    • one year ago
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    @frank0520 are you there??

  4. frank0520
    • one year ago
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    No, that is not correct

  5. MTALHAHASSAN2
    • one year ago
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    why not

  6. MTALHAHASSAN2
    • one year ago
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    x^2/2 -3^1/2

  7. frank0520
    • one year ago
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    \[\frac{ d }{ dx }(\sqrt{x^2 -3})\] \[\frac{ d }{ dx }(x^2 -3)^{1/2}\] \[\frac{ 1 }{ 2 }(x^2 -3)^{-1/2} \frac{ d }{ dx }(x^2 -3)\] \[\frac{ 1 }{ 2 }(x^2 -3)^{-1/2} (2x)\] \[x(x^2 -3)^{-1/2}\] \[\frac{ x }{ \sqrt{x^2 -3} }\]

  8. MTALHAHASSAN2
    • one year ago
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    can someone help me with it: f(x)=1/(x^2-16)^5

  9. frank0520
    • one year ago
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    Try it yourself, this is the same as the first problem. Use the chain rule.

  10. MTALHAHASSAN2
    • one year ago
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    ok let me try then

  11. MTALHAHASSAN2
    • one year ago
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    i get =1/10(x^2-16)^4

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