anonymous
  • anonymous
s=1/2n(a+K) could someone show me how to do this? im confused because i thought you had to multiply the entire equation by 2 but thats giving me wrong answer
Mathematics
katieb
  • katieb
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

freckles
  • freckles
There isn't enough information in this question.
anonymous
  • anonymous
solving for K
freckles
  • freckles
\[s=\frac{1}{2}n(a+K) ?\] If this is right, yes multiplying 2 as a first step is good. But that still will not isolate K yet. You will still have to perform more steps. Is this what you get when you multiply 2 on both sides? 2s=n(a+K) try isolating (a+k) next by undoing the multiplication by n to it.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Yeah I get that part I'm just wondering why I dont multiply a and K by 2 and it ends up being 2s=n(a+K) instead
freckles
  • freckles
are you asking why 2/2=1?
anonymous
  • anonymous
|dw:1443585029131:dw|
freckles
  • freckles
but 2/2=1
freckles
  • freckles
why you multiply one side by 4 and the other side by 2?
freckles
  • freckles
|dw:1443585130255:dw|
freckles
  • freckles
|dw:1443585146509:dw|
anonymous
  • anonymous
oh i see
anonymous
  • anonymous
i dont know i was just under the impression that if you multiply by 2 you have to do that to the entire problem but it ends up being 1 so its just a+K
freckles
  • freckles
well you have n(a+k) on the right hand side but yes you multiply 2 on both sides
freckles
  • freckles
whereas you were multiplying 2 on one side and 4 on the other side
anonymous
  • anonymous
i was canceling out the 1/2n and just putting it as n but also multiplying 2*a and 2*k because i thought when clearing fractions you had to multiply the entire equation and not just one part of it i wasnt using 4
freckles
  • freckles
you were though you multiply by 2 and then you multiply by another 2 on the right hand side and 2*2 is 4
freckles
  • freckles
see this is what you get on the right hand side side if you multiply by 4 \[4 \cdot \frac{1}{2} n (a+K) \\ \frac{4}{2}n(a+k) \\ 2n(a+k) \\ n(2a+2k)\] which is what you receive in the end on your right hand side
anonymous
  • anonymous
|dw:1443585661985:dw|
anonymous
  • anonymous
i was doing it like that
freckles
  • freckles
what happen to your n in the end? and you are still multiplying 2 on left hand side and 4 on the right hand side this incorrect you multiply both sides by the same number \[s=\frac{1}{2}n(a+k) \\ 2 \cdot (s)=2 \cdot (\frac{1}{2}n(a+k)) \\ 2s=(2 \cdot \frac{1}{2})n(a+k) \text{ since multiplication is associative } \\ 2s=(1)n(a+k) \text{ since } \frac{2}{2}=1 \\ 2s=n(a+k) \\ \text{ now try dividing both sides by } n \\ \frac{2s}{n}=a+k\] there is one last step to perform
anonymous
  • anonymous
oh it makes sense
anonymous
  • anonymous
i was distributing it wrong when its already being canceled out

Looking for something else?

Not the answer you are looking for? Search for more explanations.