A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
∆ABC has vertices A(0, 0), B(2, 4), and C(4, 2). ∆RST has vertices R(0, 3), S(1, 5), and T(2, 4). Prove that ∆ABC ∼ ∆RST. (Hint: Graph ∆ABC and ∆RST in the coordinate plane.)
anonymous
 one year ago
∆ABC has vertices A(0, 0), B(2, 4), and C(4, 2). ∆RST has vertices R(0, 3), S(1, 5), and T(2, 4). Prove that ∆ABC ∼ ∆RST. (Hint: Graph ∆ABC and ∆RST in the coordinate plane.)

This Question is Closed

dm91
 one year ago
Best ResponseYou've already chosen the best response.0@steve816 he can help you i think.

steve816
 one year ago
Best ResponseYou've already chosen the best response.3Well, do you know how to plot points on the coordinate plane? All you do is draw the points and connect the dots.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so how do i do this problem?

dm91
 one year ago
Best ResponseYou've already chosen the best response.0ok so as steve put it do you have a graph?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ive already graphed the points but i dont know how to prove it similar

steve816
 one year ago
Best ResponseYou've already chosen the best response.3If the triangles are the same size once you graphed, then they are similar.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i thought you had to do the distance formula?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0they werent the same size

steve816
 one year ago
Best ResponseYou've already chosen the best response.3Yes, you can use the distance formula

steve816
 one year ago
Best ResponseYou've already chosen the best response.3For each of the sides

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay how can i do it with the distance formula?

steve816
 one year ago
Best ResponseYou've already chosen the best response.3Plug in your (x, y) coordinates into this formula: http://2.bp.blogspot.com/GMrbM3fg4NU/VHljne7DleI/AAAAAAAABec/3emecyWG4ew/s1600/Slide1.jpg

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait which numbers do i put into it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i did AB and got 20 is that correct?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@steve816 is that correct?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i need help fast can someone help?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i got the squareroot of 20 for AB

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0for rs i got the sqaureroot of 5 is that correct?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and for CT i got the sqareroot of 40 is that correct?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok what do i do now?

dm91
 one year ago
Best ResponseYou've already chosen the best response.0no that one would have to be up to Steve because he gave you the square root idea but i might be able to get you someone else that can help because Steve is helping other pp at the time.

Koikkara
 one year ago
Best ResponseYou've already chosen the best response.0Hai, how can i help you ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i was doing the distance formula for the problem and dont know what to do next

Koikkara
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443591908295:dw According to your question..

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i did Ab and got the squareroot of 20 then i did RS and got the sqareroot of 5 then i did CT and got the squareroot of 40

Koikkara
 one year ago
Best ResponseYou've already chosen the best response.0hmm... better, this user @dan815 can help you more clearly.

zpupster
 one year ago
Best ResponseYou've already chosen the best response.0this is cheating a bit becasue this program gives the lentgh of the sides but you need to use the SSS postulate and this is easier because 2 side length are the same \[\frac{ BC}{ EF} = \frac{ AB }{DF} \]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.