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I don't think it's factorable...
Oh...I got stuck at (a+b)(a-b)-4(b+1). Thanks! For some reason, if you insert the equation into http://www.wolframalpha.com/widgets/view.jsp?id=e7040eab64a24724666a4991fb077bd2, it can be factorable
^^wolfram factoring calculator http://www.wolframalpha.com/widgets/view.jsp?id=e7040eab64a24724666a4991fb077bd2
a^2 - b^2 -4b - 4 = a^2 - ( b^2 +4b + 4)
This expression is the difference of the perfect square a^2 and the perfect square trinomial ( b^2 +4b + 4)
Yes, that was what the answer was suppose to be. I always end up grouping the wrong polynomials. Thanks.
a^2 - ( b^2 + 4b + 4) = a^2 - [(b + 2)*(b+2)] = a^2 - ( b + 2)^2 =
a^2 - ( b + 2)^2 = ? @one234 (I grouped the wrong ones together on my first try, too. :) )
a^2 - ( b + 2)^2 = [ a + (b + 2 ) ] * [ a - ( b + 2 ) ]
I think you have a sign error in distributing the negative here: [ a - ( b + 2 ) ]
- ( b + 2 ) The negative applies to both the b and the 2. So, what would be the correct answer? @one2345 (Or, did I mess up?)
(a-b-2) I didn't realize it was necessary to use the parentheses. :P
[ a + (b + 2 ) ] * [ a - ( b + 2 ) ] = (a + b + 2) * (a - b - 2)
Thank you again.
would you mind showing me how to do one more factoring problem?
Could you check my work for this problem? I did something wrong...
@one2345 Good work!
I was doing this on paper and I just realized my error and corrected it online. Anyway, thank you so much for helping me. I really appreciate it.
You are welcome. If you want to practice tomorrow, I'll look for you.
That's fine. :) I'm studying today for a factoring quiz i have tomorrow. I have to leave now, good night!