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ParthKohli

  • one year ago

this is incomplete argh

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  1. ParthKohli
    • one year ago
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    |dw:1443611451350:dw|

  2. ParthKohli
    • one year ago
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    |dw:1443611647543:dw|

  3. ParthKohli
    • one year ago
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    Find the minimum value of \(v\) given all that.

  4. ParthKohli
    • one year ago
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    In the vertical direction,\[\frac{a}{\sqrt{2}} + b\frac{\sqrt{3}}{2} = 5g\]

  5. ParthKohli
    • one year ago
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    In the horizontal direction,\[\frac{a}{\sqrt{2}} + \frac{b}2 = \frac{5v^2}{1.6}\]

  6. ParthKohli
    • one year ago
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    \[v = \sqrt{0.32 \left(\frac{a}{\sqrt 2} + \frac{b}{2}\right)}\] http://www.wolframalpha.com/input/?i=minimise+sqrt%280.32*%28a%2F2+%2B+b%2Fsqrt%282%29%29%29+constrained+to+sqrt%283%29%2F2*a+%2B+b%2Fsqrt%282%29+%3D+50

  7. anonymous
    • one year ago
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    Can someone please help me??????

  8. anonymous
    • one year ago
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    seriously people?!?!?!

  9. ganeshie8
    • one year ago
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    we want to find the minimum value of \(v\), not the exact value of \(v\) so the problem is fine i think

  10. ParthKohli
    • one year ago
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    yes, and it's turning out to be zero.

  11. ganeshie8
    • one year ago
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    the greater the linear velocity, the greater will be the tension in wires in which wire do you think the tension will be more ?

  12. IrishBoy123
    • one year ago
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    the minimum value will occur when the tension in the lower string/rod = 0

  13. ganeshie8
    • one year ago
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    for a given linear velocity, which wire experiences more tension, AC or BC ?

  14. ParthKohli
    • one year ago
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    @IrishBoy123 why?!

  15. IrishBoy123
    • one year ago
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    https://www.desmos.com/calculator

  16. ParthKohli
    • one year ago
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    ooo, I forgot to add the fact that a>0, b>0

  17. IrishBoy123
    • one year ago
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    if you start it spinning from zero, all the tension will be in the longer string so in the plot follow that red circle out to where it meets the blue circle. that is the cross over

  18. mathmate
    • one year ago
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    @IrishBoy123 Agree! By intuition, I believe that any one time, only one wire will be in tension. There is (perhaps) exactly one value of v that will give T1>0 and T2>0 on both wires because of the physical arrangement. (assuming the wires don't take compression).

  19. IrishBoy123
    • one year ago
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    yeah, @mathmate if these are rods ....

  20. ParthKohli
    • one year ago
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    Yes, the minimum occurs when the tension in the lower string is zero.

  21. ParthKohli
    • one year ago
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    In other words, you mean that if we want to decrease velocity, we increase the radius.

  22. ParthKohli
    • one year ago
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    Thanks guys.

  23. IrishBoy123
    • one year ago
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    this is what i meant to share in that link...when i was talking about red and blue circles |dw:1443613483068:dw|

  24. ParthKohli
    • one year ago
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    wait, I'm confused again.

  25. ParthKohli
    • one year ago
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    what are those red and blue circles?

  26. IrishBoy123
    • one year ago
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    |dw:1443613751302:dw|

  27. IrishBoy123
    • one year ago
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    circles show the radii of the taut strings

  28. ParthKohli
    • one year ago
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    oh.

  29. IrishBoy123
    • one year ago
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    assuming these are strings, if you started at v = 0 and slowly increased the rotat speed, it would be supported by the red string [the higher one] until you reach crossover

  30. IrishBoy123
    • one year ago
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    so analyse it as a 1 string prpblem where you know that the one string has to reach an angle of 30 degrees \(T = \dfrac{mv^2}{r \sin 30} = \dfrac{mg}{ \cos 30}\)

  31. ParthKohli
    • one year ago
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    this is great! thanks!

  32. mathmate
    • one year ago
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    @irishboy Exactly. I have done just that, and there is no point where both wires are taut. Analyzing separately, the long wire will attain 30 degrees at about 3 m/s. The short wire will attain 45 degrees at almost 4 m/s. So there is no point (velocity-wise) where both wires will be taut.

  33. IrishBoy123
    • one year ago
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    cool!

  34. anonymous
    • one year ago
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    Can someone please help me??

  35. anonymous
    • one year ago
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    Help Me ...Easy Medal ^^^

  36. anonymous
    • one year ago
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    Determine algebraically whether the function is even, odd, or neither even nor odd. f(x) = -3x4 - 2x - 5 Neither Even Odd

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