ParthKohli
  • ParthKohli
this is incomplete argh
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
ParthKohli
  • ParthKohli
|dw:1443611451350:dw|
ParthKohli
  • ParthKohli
|dw:1443611647543:dw|
ParthKohli
  • ParthKohli
Find the minimum value of \(v\) given all that.

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More answers

ParthKohli
  • ParthKohli
In the vertical direction,\[\frac{a}{\sqrt{2}} + b\frac{\sqrt{3}}{2} = 5g\]
ParthKohli
  • ParthKohli
In the horizontal direction,\[\frac{a}{\sqrt{2}} + \frac{b}2 = \frac{5v^2}{1.6}\]
ParthKohli
  • ParthKohli
\[v = \sqrt{0.32 \left(\frac{a}{\sqrt 2} + \frac{b}{2}\right)}\]http://www.wolframalpha.com/input/?i=minimise+sqrt%280.32*%28a%2F2+%2B+b%2Fsqrt%282%29%29%29+constrained+to+sqrt%283%29%2F2*a+%2B+b%2Fsqrt%282%29+%3D+50
anonymous
  • anonymous
Can someone please help me??????
ganeshie8
  • ganeshie8
http://www.wolframalpha.com/input/?i=solve+%5Cfrac%7Ba%7D%7B%5Csqrt%7B2%7D%7D+%2B+b%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B2%7D+%3D+5*9.8%2C+%5Cfrac%7Ba%7D%7B%5Csqrt%7B2%7D%7D+%2B+%5Cfrac%7Bb%7D2+%3D+%5Cfrac%7B5v%5E2%7D%7B1.6%7D%2Cb%3D0
anonymous
  • anonymous
seriously people?!?!?!
ganeshie8
  • ganeshie8
we want to find the minimum value of \(v\), not the exact value of \(v\) so the problem is fine i think
ParthKohli
  • ParthKohli
yes, and it's turning out to be zero.
ganeshie8
  • ganeshie8
the greater the linear velocity, the greater will be the tension in wires in which wire do you think the tension will be more ?
IrishBoy123
  • IrishBoy123
the minimum value will occur when the tension in the lower string/rod = 0
ganeshie8
  • ganeshie8
for a given linear velocity, which wire experiences more tension, AC or BC ?
ParthKohli
  • ParthKohli
@IrishBoy123 why?!
IrishBoy123
  • IrishBoy123
https://www.desmos.com/calculator
ParthKohli
  • ParthKohli
ooo, I forgot to add the fact that a>0, b>0
ParthKohli
  • ParthKohli
http://www.wolframalpha.com/input/?i=minimise+sqrt%280.32*%28a%2F2+%2B+b%2Fsqrt%282%29%29%29+constrained+to+sqrt%283%29%2F2*a+%2B+b%2Fsqrt%282%29+%3D+5*9.8%2C+a%3E0%2C+b%3E0 about 3 m/s
IrishBoy123
  • IrishBoy123
if you start it spinning from zero, all the tension will be in the longer string so in the plot follow that red circle out to where it meets the blue circle. that is the cross over
mathmate
  • mathmate
@IrishBoy123 Agree! By intuition, I believe that any one time, only one wire will be in tension. There is (perhaps) exactly one value of v that will give T1>0 and T2>0 on both wires because of the physical arrangement. (assuming the wires don't take compression).
IrishBoy123
  • IrishBoy123
yeah, @mathmate if these are rods ....
ParthKohli
  • ParthKohli
Yes, the minimum occurs when the tension in the lower string is zero.
ParthKohli
  • ParthKohli
In other words, you mean that if we want to decrease velocity, we increase the radius.
ParthKohli
  • ParthKohli
Thanks guys.
IrishBoy123
  • IrishBoy123
this is what i meant to share in that link...when i was talking about red and blue circles |dw:1443613483068:dw|
ParthKohli
  • ParthKohli
wait, I'm confused again.
ParthKohli
  • ParthKohli
what are those red and blue circles?
IrishBoy123
  • IrishBoy123
|dw:1443613751302:dw|
IrishBoy123
  • IrishBoy123
circles show the radii of the taut strings
ParthKohli
  • ParthKohli
oh.
IrishBoy123
  • IrishBoy123
assuming these are strings, if you started at v = 0 and slowly increased the rotat speed, it would be supported by the red string [the higher one] until you reach crossover
IrishBoy123
  • IrishBoy123
so analyse it as a 1 string prpblem where you know that the one string has to reach an angle of 30 degrees \(T = \dfrac{mv^2}{r \sin 30} = \dfrac{mg}{ \cos 30}\)
ParthKohli
  • ParthKohli
this is great! thanks!
mathmate
  • mathmate
@irishboy Exactly. I have done just that, and there is no point where both wires are taut. Analyzing separately, the long wire will attain 30 degrees at about 3 m/s. The short wire will attain 45 degrees at almost 4 m/s. So there is no point (velocity-wise) where both wires will be taut.
IrishBoy123
  • IrishBoy123
cool!
anonymous
  • anonymous
Can someone please help me??
anonymous
  • anonymous
Help Me ...Easy Medal ^^^
anonymous
  • anonymous
Determine algebraically whether the function is even, odd, or neither even nor odd. f(x) = -3x4 - 2x - 5 Neither Even Odd

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