A community for students.
Here's the question you clicked on:
 0 viewing
ParthKohli
 one year ago
this is incomplete argh
ParthKohli
 one year ago
this is incomplete argh

This Question is Closed

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443611451350:dw

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.0dw:1443611647543:dw

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.0Find the minimum value of \(v\) given all that.

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.0In the vertical direction,\[\frac{a}{\sqrt{2}} + b\frac{\sqrt{3}}{2} = 5g\]

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.0In the horizontal direction,\[\frac{a}{\sqrt{2}} + \frac{b}2 = \frac{5v^2}{1.6}\]

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.0\[v = \sqrt{0.32 \left(\frac{a}{\sqrt 2} + \frac{b}{2}\right)}\] http://www.wolframalpha.com/input/?i=minimise+sqrt%280.32*%28a%2F2+%2B+b%2Fsqrt%282%29%29%29+constrained+to+sqrt%283%29%2F2*a+%2B+b%2Fsqrt%282%29+%3D+50

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can someone please help me??????

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0seriously people?!?!?!

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0we want to find the minimum value of \(v\), not the exact value of \(v\) so the problem is fine i think

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.0yes, and it's turning out to be zero.

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0the greater the linear velocity, the greater will be the tension in wires in which wire do you think the tension will be more ?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.4the minimum value will occur when the tension in the lower string/rod = 0

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0for a given linear velocity, which wire experiences more tension, AC or BC ?

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.0ooo, I forgot to add the fact that a>0, b>0

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.4if you start it spinning from zero, all the tension will be in the longer string so in the plot follow that red circle out to where it meets the blue circle. that is the cross over

mathmate
 one year ago
Best ResponseYou've already chosen the best response.2@IrishBoy123 Agree! By intuition, I believe that any one time, only one wire will be in tension. There is (perhaps) exactly one value of v that will give T1>0 and T2>0 on both wires because of the physical arrangement. (assuming the wires don't take compression).

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.4yeah, @mathmate if these are rods ....

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.0Yes, the minimum occurs when the tension in the lower string is zero.

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.0In other words, you mean that if we want to decrease velocity, we increase the radius.

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.4this is what i meant to share in that link...when i was talking about red and blue circles dw:1443613483068:dw

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.0wait, I'm confused again.

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.0what are those red and blue circles?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.4dw:1443613751302:dw

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.4circles show the radii of the taut strings

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.4assuming these are strings, if you started at v = 0 and slowly increased the rotat speed, it would be supported by the red string [the higher one] until you reach crossover

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.4so analyse it as a 1 string prpblem where you know that the one string has to reach an angle of 30 degrees \(T = \dfrac{mv^2}{r \sin 30} = \dfrac{mg}{ \cos 30}\)

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.0this is great! thanks!

mathmate
 one year ago
Best ResponseYou've already chosen the best response.2@irishboy Exactly. I have done just that, and there is no point where both wires are taut. Analyzing separately, the long wire will attain 30 degrees at about 3 m/s. The short wire will attain 45 degrees at almost 4 m/s. So there is no point (velocitywise) where both wires will be taut.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can someone please help me??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Help Me ...Easy Medal ^^^

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Determine algebraically whether the function is even, odd, or neither even nor odd. f(x) = 3x4  2x  5 Neither Even Odd
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.