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phi
 one year ago
Best ResponseYou've already chosen the best response.1do you see the 5x term? take the 5 from that term, divide it by 2 \[ \frac{5}{2}\] then square it \[ \frac{25}{4} \] add that to both sides of the equation

Diana.xL
 one year ago
Best ResponseYou've already chosen the best response.0my answer would be b?

phi
 one year ago
Best ResponseYou've already chosen the best response.1what do you get after adding 25/4 to both sides of the equation?

phi
 one year ago
Best ResponseYou've already chosen the best response.1you should get \[ x^2 +5x + \frac{25}{4}= 1 + \frac{25}{4}\]

phi
 one year ago
Best ResponseYou've already chosen the best response.1the left side is a perfect square (that is why you add 25/4) it is \[ \left(x+ \frac{5}{2}\right)^2 = 1 + \frac{25}{4} \] I would write the 1 as 4/4 \[ \left(x+ \frac{5}{2}\right)^2 = \frac{4}{4} + \frac{25}{4} \]

phi
 one year ago
Best ResponseYou've already chosen the best response.1on the right side you have two fractions with the same denominator, so you can add the tops

phi
 one year ago
Best ResponseYou've already chosen the best response.1yes \[ \left(x+ \frac{5}{2}\right)^2 = \frac{21}{4} \] if you take the square root (of both sides to keep it equal) we get rid of the square on the left side \[ \left(x+ \frac{5}{2}\right)= \pm \sqrt\frac{21}{4} \\ x+ \frac{5}{2}= \pm\frac{\sqrt{21}}{2} \] now add 5/2 to both sides

phi
 one year ago
Best ResponseYou've already chosen the best response.1you get \[ x= \frac{5 \pm \sqrt{21}}{2} \]
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