A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
The sum of the squares of three negative numbers p,q,r equals the sum of the products of all possible pairs of the three numbers. Which of the following equals p3qr2 ?
1) (pq + qr + rp)3
2) q2(p3r + rp3)/2
anonymous
 one year ago
The sum of the squares of three negative numbers p,q,r equals the sum of the products of all possible pairs of the three numbers. Which of the following equals p3qr2 ? 1) (pq + qr + rp)3 2) q2(p3r + rp3)/2

This Question is Closed

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.2we're given : \(p^2+q^2+r^2 = pq=qr=rp\) so, \(p^3qr^2 = pq*(pr)^2 = (p^2+q^2+r^2)^3\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Right answer id option 2 @ganeshie8

TuringTest
 one year ago
Best ResponseYou've already chosen the best response.1"The sum of the squares of three negative numbers p,q,r equals the *sum* of the products of all possible pairs of the three numbers." I think we are given that\[p^2+q^2+r^2=pq+qr+rp\]I could be wrong; I'm a bit rusty...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Which of the following equals p3qr2 ?@TuringTest

TuringTest
 one year ago
Best ResponseYou've already chosen the best response.1I'm pretty bad at these problems, but\[p^2=pq+qr+rpq^2r^2\]\[r^2=pq+qr+rpq^2p^2\]\[pq=p^2+q^2+r^2qrrp\]multiplying all that out should give an answer, but I'm sure there's a smarter way to do it.

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1something is off.. the answer is q2(p3r + rp3)/2 <<p^3 r and r p^3 are same!!>> which means p^3 q r^2 = q^2(p^3 r + rp^3)/2 holds true p^3 and q can be factored out from the right and gets cancelled, r^2 = q (r+r)/2 = rq r= q holds true ...
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.