The sum of two consecutive integers is at most 223. What is the larger of the two integers?

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The sum of two consecutive integers is at most 223. What is the larger of the two integers?

Mathematics
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it can be any 2 integers (up to a certain level) because it tells you that the sum is AT MOST 223 for instance 1 & 2 2 & 3 18&19 all satisfy that inequality. In general if you have an interger x then the next integer is x+1 so the sum of 2 consecutive integers = 2x+1 you can use that to find the LARGEST possible number (but that is not what the question asks..)
SO 3?

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no as i said for instanc 18&19 but also 100 & 101 READ what I said
OK so what you just posted is 100 and 101.. The larger is 101
you have missed the point What about 101 & 102 ? Have a little think before you post next
x + x+ 1 <= 223
Did you type the question exactly as written?
How am I missing the point?? The LARGER is the higher number....Therefore out of 102 its 103
And yes I did!
what about 103 & 104 have a think and read teh question
x + x + 1 <= 223 2x <= 222 x <= 111 x + 1 = 111 + 1 = 112
but the way the question is worded can be a bit confusing
Very confusing!
to be honest - this is not a well phrased question - it doesn't really have an answer as written. What @texaschic101 has done is given you the answer for a differnt question "what is the LARGEST possible value for one of the integers" but that is not what is asked
true ^^.....I think the way it is written, there can be more then 1 answer
So this question is a tricky question or it didnt make it right
its tricky
ahhhhhhhh!
So what is the 2 answers you guys see?
Please have a think and try to understand what we are saying it is not 2 answers - it is a NUMBER of answers ANY 2 integers less than 112 will answer teh question correctly. You need to look at the equation that was written above and understand HOW it relates to rthe question. doi not focus on the answer - this question does not have a proper answer
I dont see an equation!
IF the question was written properly then it would not be 'tricky' the some of integer x and the consecutive integer (x+1) is x+x+1 = 2x+1 THAT is the key point you needed to get to answer similar questions
@texaschic101 wrote THIS eqution above x + x + 1 <= 223 2x <= 222 x <= 111 x + 1 = 111 + 1 = 112 BUT it doesn't answer your question, because your question is not posed properly
Ok is there a way to solve this????
I repeat: it is not 2 answers - it is a NUMBER of answers ANY 2 integers less than 112 will answer the question correctly.
11,13,15 and 17
what i found
−112,−56,−28,−16,−14,−8,−7,−4,−2,−1,1,2,4,7,8,14,16,28,56,112
Thats it
I am sorry buddy...I just don't know...there can be several answers
:(

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