A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

2SO2 (g) + O2 (g) 2SO3 (g) + heat. What will happen if more sulfur trioxide gas is added to the reaction mixture?

  • This Question is Closed
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    a-The equilibrium will shift toward the products. b-The equilibrium will shift toward the reactants. c-Keq will increase. d-Keq will decrease. e-There will be no shift in equilibrium.

  2. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @Missiey

  3. Photon336
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Keq cant decrease or increase it's a constant value at a particular temp. you would have to change temp for this to happen. @bransonsmommy what do you think the answer is

  4. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    would it be E then? @Photon336

  5. Photon336
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    why do you think it's E

  6. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    it was kind of a guess but if it cant increase or decrease it cant be C or D, but E just looked like the best guess to me, im not to good in chem :/

  7. Photon336
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    well @bransonsmommy it will have an effect. think about it like this the reaction is already at equilibrium, so there's a certain amount of reactants and products at equilibrium for this reaction. if we add more on one side, we call that a stress, the reaction has to adjust to that stress. follow so far?

  8. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    somewhat, i'm leaning towards A, but i am still a little fuzzy on this...

  9. Photon336
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    @bransonsmommy \[Keq = \frac{ products }{ reactants } = \frac{ [C]^{}[D] }{ [A][B] }\]

  10. Photon336
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    first do you understand what equilibrium is? @bransonsmommy

  11. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    not really.. im doing online classes and they give us no notes or anything..

  12. Photon336
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    ok

  13. Photon336
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    when you have a reaction, say you have a bridge right? the products are on one side the reactants are on the other. the reaction will proceed until it reaches a point where the rate of forward reaction = the rate of the reverse reaction, that's equilibrium a little analogy here is the number of cars going back and forth is the same. Equilibrium does not mean that the concentrations of the reactants and products are equal. Can you see why? Also what is favored in this reaction, reactants or products? at equilibrium |dw:1443623016742:dw|

  14. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i think i kinda get it a little better, so the answer would be B?

  15. Photon336
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    yeah i would say so

  16. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thank you!

  17. Photon336
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    but there's a lot to be learned here at least @bransonsmommy, sometimes they give you Keq value and sometimes they dont for this question they didn't. like if i gave you a keq of 10^6 at 25 C what type of reaction is this? how do you know what does it favor?

  18. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.