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mathmath333
 one year ago
How to quickly calculate 5!/e
mathmath333
 one year ago
How to quickly calculate 5!/e

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mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0\(\large \color{black}{\begin{align} & \normalsize \text{ How to quickly calculate}\hspace{.33em}\\~\\ & \lfloor{\dfrac{5!}{e}\rfloor} \hspace{.33em}\\~\\ \end{align}}\)

mathmate
 one year ago
Best ResponseYou've already chosen the best response.2Do you mean pen and paper or mentally?

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0by pen and paper (hand)

mathmate
 one year ago
Best ResponseYou've already chosen the best response.2So would that not be 120/2.718281828?

mathmate
 one year ago
Best ResponseYou've already chosen the best response.2Or you can do a quick mental approximation by 120/2.7=40/0.9=44.4

mathmate
 one year ago
Best ResponseYou've already chosen the best response.2If you want to refine it, subtract 2/300 of the calculated value (mentally if you want) to get 44.15 Accurate value is 44.14553294057308

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0it should be correct

mathmate
 one year ago
Best ResponseYou've already chosen the best response.2Interesting problem. Will be back.

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0ur thinking is correct of \(\approx n/2.7\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0trying to learn derangements? :)

mathmate
 one year ago
Best ResponseYou've already chosen the best response.2As long as it is between 44 and 45, the floor function will convert it to 44. We need additional accuracy to get the lower bound so it doesn't go below 44.

mathmath333
 one year ago
Best ResponseYou've already chosen the best response.0nice forecasting of dearrangments.
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