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thcsbabygirl1224

  • one year ago

help me please 4x+y+5z=-9 x-4y-2x+-2 2x+3y-2z=21

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  1. anonymous
    • one year ago
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    Use matrix

  2. thcsbabygirl1224
    • one year ago
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    what its a system of equations solving for 3 variables so im lost

  3. thcsbabygirl1224
    • one year ago
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    @hartnn

  4. thcsbabygirl1224
    • one year ago
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    @LazyBoy @hba

  5. thcsbabygirl1224
    • one year ago
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    @chainedecho

  6. Loser66
    • one year ago
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    The second equation should be x-4y-2z =-2, right?

  7. thcsbabygirl1224
    • one year ago
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    yes

  8. Loser66
    • one year ago
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    take the third one subtract the second one, what do you get? that is (3) -(2) =??

  9. thcsbabygirl1224
    • one year ago
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    i am trying to get rid of the x in all 3 equations so i have to set them to 0 im lost on the work

  10. Loser66
    • one year ago
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    YOu lost on your way, give it a try on my way, ok? Again (equation 3 )-(equation 2) is??? You should work on it, I am guiding you only.

  11. thcsbabygirl1224
    • one year ago
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    @kal1921 what is the matrics

  12. Loser66
    • one year ago
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    Good luck.

  13. thcsbabygirl1224
    • one year ago
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    ok i have now -2x-4y-2z=-4 2x+3y-2z=21

  14. thcsbabygirl1224
    • one year ago
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    @Michele_Laino

  15. Michele_Laino
    • one year ago
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    here, you have a system of two equations, with three unknows. We can rewrite it as below: \[\left\{ \begin{gathered} 2x + 4y = 4 - 2z \hfill \\ 2x + 3y = 21 + 2z \hfill \\ \end{gathered} \right.\] which can, easily solved for x, and y as functions of z. Please try

  16. thcsbabygirl1224
    • one year ago
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    You get 7y-4z=16

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