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anonymous

  • one year ago

Charlie's Computer Company charges $0.65 per pound to ship computers. Part A: Write an equation to determine the total cost, c, to ship p pounds of computers. Use your equation to determine the cost of shipping 2 pounds of computers. (6 points) Part B: If the company reduces the cost to ship computers by 0.05 per pound, write an equation to determine the total cost, c, to ship p pounds of computers with the reduced cost. (4 points)

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  1. anonymous
    • one year ago
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    @Michele_Laino

  2. Michele_Laino
    • one year ago
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    hint: if one pound costs 0.65 dollars, then p pounds cost: 0.65*p

  3. anonymous
    • one year ago
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    are we doing part a?

  4. Michele_Laino
    • one year ago
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    yes!

  5. anonymous
    • one year ago
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    okay.. 0.65p ?

  6. Michele_Laino
    • one year ago
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    correct! \[c = 0.65 \cdot p\]

  7. anonymous
    • one year ago
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    so what do we say for part a?

  8. Michele_Laino
    • one year ago
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    we can say this: "the requested equation, is: \(c = 0.65 \cdot p\)"

  9. anonymous
    • one year ago
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    ok and part b?

  10. Michele_Laino
    • one year ago
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    now, we have to replace p with 2, so we get: \[c = 0.65 \cdot p = 0.65 \cdot 2 = ...?\]

  11. anonymous
    • one year ago
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    i dont know that one :(

  12. Michele_Laino
    • one year ago
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    it is simple: c=0.65*2=1.3 dollars

  13. anonymous
    • one year ago
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    oh okay.. :)

  14. Michele_Laino
    • one year ago
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    for part B) if one pound is shipped for 0.05 dollars, then p pounds are shipped for: 0.05*p

  15. anonymous
    • one year ago
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    what do we say for part b?

  16. Michele_Laino
    • one year ago
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    we can write this statement: "the cost to ship \(p\) pounds, with the reduced unitary cost is \(c=0.05 \cdot p\)"

  17. anonymous
    • one year ago
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    so whats part A and Part B... please include all of the work :)

  18. Michele_Laino
    • one year ago
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    summarizing, we can write this: part A) requested formula is \(c=0.65 \cdot p \) so, specializing to p=2, we have: \(c=0.65 \cdot 2=1.30$\) part B) the new formula, using the reduced unitary cost, is: \(c=0.05 \cdot p \)

  19. anonymous
    • one year ago
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    ok thanks :) i have more questions :)

  20. Michele_Laino
    • one year ago
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    please wait, since someone has tagged me

  21. anonymous
    • one year ago
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    okay ;)

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