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nthenic_oftime
 one year ago
please help.. idk how to even figure this out so steps would be nice too.
Find the specified vector or scalar.
u = 4i + 1j and v = 4i + 1j; Find . u+v
A. Sqrt34
B. 8
C. 5
D. 2
nthenic_oftime
 one year ago
please help.. idk how to even figure this out so steps would be nice too. Find the specified vector or scalar. u = 4i + 1j and v = 4i + 1j; Find . u+v A. Sqrt34 B. 8 C. 5 D. 2

This Question is Closed

phi
 one year ago
Best ResponseYou've already chosen the best response.1first add the "corresponding" terms then find the length of the resulting vector (length is sqrt(sum of square of each term))

phi
 one year ago
Best ResponseYou've already chosen the best response.1for example the length of 3i+4j is \[ \sqrt{3^2+4^2} = \sqrt{9+16}= \sqrt{25} = 5\]

nthenic_oftime
 one year ago
Best ResponseYou've already chosen the best response.1hey thank you for that a answer can you show me how you got got the length of the vector

nthenic_oftime
 one year ago
Best ResponseYou've already chosen the best response.1wait i misunderstood i thought that was the same thing. im so confused

nthenic_oftime
 one year ago
Best ResponseYou've already chosen the best response.1first add corresponding terms gives us... i+2j ?

nthenic_oftime
 one year ago
Best ResponseYou've already chosen the best response.1idk how to find the length of a vector

nthenic_oftime
 one year ago
Best ResponseYou've already chosen the best response.1i dont understand the whole vector and scalar thing

phi
 one year ago
Best ResponseYou've already chosen the best response.1yes, the i's "go away" you are left with 2j

nthenic_oftime
 one year ago
Best ResponseYou've already chosen the best response.1which is positive points?

phi
 one year ago
Best ResponseYou've already chosen the best response.1in 2dimensions, you can think of the vector as <x,y> pair of numbers for example, u= 4i + 1j (which can also be written <4,1> in a graph, it looks like this: dw:1443634973472:dw

phi
 one year ago
Best ResponseYou've already chosen the best response.1and the length of the vector is the length of the line from (0,0) (the origin) to the point (4,1) we use pythagoras to find its length

nthenic_oftime
 one year ago
Best ResponseYou've already chosen the best response.1okay so U is a vector and length would be to the point.

nthenic_oftime
 one year ago
Best ResponseYou've already chosen the best response.1oh okay i didnt see your message

phi
 one year ago
Best ResponseYou've already chosen the best response.1u+v = 2j (or 0i+2j, or (0,2) ) in a graph it looks like this dw:1443635111360:dw

nthenic_oftime
 one year ago
Best ResponseYou've already chosen the best response.1dw:1443635167339:dw

phi
 one year ago
Best ResponseYou've already chosen the best response.1we could use pythagoras \[ \sqrt{0^2+2^2}= \sqrt{0+4}= \sqrt{4}= 2 \] but we can see the length is just 2

nthenic_oftime
 one year ago
Best ResponseYou've already chosen the best response.1oh cool good so our drawings of vthis match okay so 0^2 because we have no i left and 2^2 becayse 2j

nthenic_oftime
 one year ago
Best ResponseYou've already chosen the best response.1i understand thank you so much... can i ask what do i and j standfor why not use x and y? i got behind and i am trying to catch up on things as its obvious i am missing a gfew things in my knowledge

phi
 one year ago
Best ResponseYou've already chosen the best response.1The interesting thing is this same idea works for 3D or even higher dimensions (though visualizing a vector with more than 3 components is beyond me)

phi
 one year ago
Best ResponseYou've already chosen the best response.1I'm not sure why people use i,j,k but it does not matter the idea is they are different "dimensions" for example, sideways and up/down. The other way people write vectors is as a "tuple" such as (1,2) or <1,2> where it is understood each number is the distance along each dimension

nthenic_oftime
 one year ago
Best ResponseYou've already chosen the best response.1okay so vectors would be written as plot points or coordinates just signified as different dimensions thanks for the help on the problem and that little info there it caught me up a lil bit. medal and fan for you :)
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