## ashontae19 one year ago I need help on a math worksheet on graphs i will give medals. Anyone down?

1. ashontae19

@Michele_Laino

2. Michele_Laino

3. ashontae19

@Michele_Laino

4. ashontae19

@iwanttogotostanford

5. ashontae19

@geny55

6. ashontae19

can anyone help me?

7. Michele_Laino

the requested climb is missing

8. Michele_Laino

you have to draw an initial climb, a loop and at least two hills

9. ashontae19

I did that on my graph as you can see i need to correct it

10. Michele_Laino

I'm thinking to a graph like this: |dw:1443635422403:dw|

11. ashontae19

so plot the coordinates where?

12. Michele_Laino

here are the requested coordinates: |dw:1443635532120:dw|

13. Michele_Laino

furthermore: |dw:1443635766113:dw|

14. ashontae19

ok hold on im going to take a picture if it is correct

15. Michele_Laino

ok!

16. ashontae19

can you see it?

17. Michele_Laino

yes! nevertheless is not a good graph, please, redo your graph using my suggestions |dw:1443636162091:dw|

18. ashontae19

ok can you see where i need to draw the coordinates? @Michele_Laino

19. Michele_Laino

I think that you have to specify the coordinates at the second end of the initial climb, like in my drawing

20. Michele_Laino

|dw:1443636688896:dw|

21. ashontae19

ok im drawing it now

22. Michele_Laino

ok! it is useful to write the requested answers

23. Michele_Laino

now, you have to specify the coordinates of the subsequent points: |dw:1443637076815:dw| namely, you have to specify the coordinates for each point at the top of the two hills

24. Michele_Laino

please, complete this table: second end---> x=...? y=...? point at the top of the first hill---> x=....? y=...? point at the top at the second hill---> x=...? y=...?

25. ashontae19

like you want me to plot the points the chart you typed?

26. Michele_Laino

no, you have to draw, on your graph the points like in my drawing. then you have to write their coordinates, referring to your drawing

27. ashontae19

the second end is 4,5 correct?

28. Michele_Laino

I see (5,5)

29. ashontae19

correct. to find the slope i would do y2-y1/x2-x1 with what points?

30. Michele_Laino

yes!

31. ashontae19

with 5,5 and what other point?

32. Michele_Laino

it is the origin of the cartesian system, namely (0,0)

33. ashontae19

the slope would be 1 correct?

34. Michele_Laino

correct!

35. Michele_Laino

36. ashontae19

ok. when you get back just to ask is the equation y=x?

37. Michele_Laino

yes! correct!

38. Michele_Laino

now, you would write the coordinates of the subsequent four points: |dw:1443638327046:dw| namely the points at the top and at the bottom of each hill

39. ashontae19

ok so what would be the domain and range?

40. ashontae19

ok i did that @Michele_Laino

41. Michele_Laino

looking at your drawing I see that your roller coaster starts at the point (0,0) and continues to the point (16,1)

42. Michele_Laino

so the domain is the segment: $$[0,16]$$

43. Michele_Laino

whereas the range is the segment $$[0,5]$$ approximately

44. ashontae19

ok what bout the rate of change?

45. Michele_Laino

the range is given by all possible values assumed by your function

46. ashontae19

for the rate of change?

47. Michele_Laino

in order to specify the rate of change we need of the subsequent ordered pair: |dw:1443639445403:dw|

48. ashontae19

pl= 10,2?

49. ashontae19

so was i corrected?

50. Michele_Laino

better is (10, 5/2)

51. ashontae19

i thought so . for pl= 10, 5/2 and for p2 is 12 ,2

52. Michele_Laino

better is (11.5, 1.5)=(23/2, 3/2)

53. ashontae19

thats for p1 and p2?

54. Michele_Laino

yes! now you have to do this computation: $\huge r = \frac{{\frac{5}{2} - \frac{3}{2}}}{{10 - \frac{{23}}{2}}} = ...?$

55. ashontae19

-183/20?

56. Michele_Laino

hint: $\Large r = \frac{{\frac{5}{2} - \frac{3}{2}}}{{10 - \frac{{23}}{2}}} = \frac{1}{{\frac{{20 - 23}}{2}}} = \frac{2}{{20 - 23}} = ...?$

57. Michele_Laino

furthermore you have to do a similar computation for the second hill

58. Michele_Laino

for question #7, here is my hint: |dw:1443642062352:dw| as you can see at the x-ccordinate x0 corresponds two distinct y-coordinate, namely y1 and y2. What can you conclude?

59. Michele_Laino

coordinate*

60. ashontae19

hi my internet working now @Michele_Laino

61. ashontae19

@Michele_Laino when ever you get online can you help me?

62. Michele_Laino

the first rate of change is: $\Large r = \frac{{\frac{5}{2} - \frac{3}{2}}}{{10 - \frac{{23}}{2}}} = \frac{{\frac{2}{2}}}{{\frac{{20 - 23}}{2}}} = \frac{1}{{\frac{{ - 3}}{2}}} = 1 \cdot \left( { - \frac{2}{3}} \right) = ...?$

63. Michele_Laino

64. Michele_Laino

@ashontae19

65. ashontae19

-2/3?

66. Michele_Laino

yes! and for our computation we can take the absolute value, so the first rate of change is r=2/3

67. Michele_Laino

now we have to specify the points at the top and at the bottom of the second hill

68. ashontae19

so thats for the rate of change?

69. Michele_Laino

yes! it is the first rate of change, now we have to compute the rate of chage for second hill

70. ashontae19

yes

71. Michele_Laino

you have to write the coordinates of these points please: |dw:1443715743609:dw| referring your drawing

72. ashontae19

ok im going to send the picture to you

73. Michele_Laino

ok!

74. Michele_Laino

from your drawing we can see that the requested points are: (15,3) top of the hill (16,1) bottom of the hill

75. ashontae19

correct