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ashontae19

  • one year ago

I need help on a math worksheet on graphs i will give medals. Anyone down?

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  1. ashontae19
    • one year ago
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    @Michele_Laino

  2. Michele_Laino
    • one year ago
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    please, where is your mathematical graph?

  3. ashontae19
    • one year ago
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    @Michele_Laino

  4. ashontae19
    • one year ago
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    @iwanttogotostanford

  5. ashontae19
    • one year ago
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    @geny55

  6. ashontae19
    • one year ago
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    can anyone help me?

  7. Michele_Laino
    • one year ago
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    the requested climb is missing

  8. Michele_Laino
    • one year ago
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    you have to draw an initial climb, a loop and at least two hills

  9. ashontae19
    • one year ago
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    I did that on my graph as you can see i need to correct it

  10. Michele_Laino
    • one year ago
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    I'm thinking to a graph like this: |dw:1443635422403:dw|

  11. ashontae19
    • one year ago
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    so plot the coordinates where?

  12. Michele_Laino
    • one year ago
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    here are the requested coordinates: |dw:1443635532120:dw|

  13. Michele_Laino
    • one year ago
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    furthermore: |dw:1443635766113:dw|

  14. ashontae19
    • one year ago
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    ok hold on im going to take a picture if it is correct

  15. Michele_Laino
    • one year ago
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    ok!

  16. ashontae19
    • one year ago
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    can you see it?

  17. Michele_Laino
    • one year ago
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    yes! nevertheless is not a good graph, please, redo your graph using my suggestions |dw:1443636162091:dw|

  18. ashontae19
    • one year ago
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    ok can you see where i need to draw the coordinates? @Michele_Laino

  19. Michele_Laino
    • one year ago
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    I think that you have to specify the coordinates at the second end of the initial climb, like in my drawing

  20. Michele_Laino
    • one year ago
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    |dw:1443636688896:dw|

  21. ashontae19
    • one year ago
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    ok im drawing it now

  22. Michele_Laino
    • one year ago
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    ok! it is useful to write the requested answers

  23. Michele_Laino
    • one year ago
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    now, you have to specify the coordinates of the subsequent points: |dw:1443637076815:dw| namely, you have to specify the coordinates for each point at the top of the two hills

  24. Michele_Laino
    • one year ago
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    please, complete this table: second end---> x=...? y=...? point at the top of the first hill---> x=....? y=...? point at the top at the second hill---> x=...? y=...?

  25. ashontae19
    • one year ago
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    like you want me to plot the points the chart you typed?

  26. Michele_Laino
    • one year ago
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    no, you have to draw, on your graph the points like in my drawing. then you have to write their coordinates, referring to your drawing

  27. ashontae19
    • one year ago
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    the second end is 4,5 correct?

  28. Michele_Laino
    • one year ago
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    I see (5,5)

  29. ashontae19
    • one year ago
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    correct. to find the slope i would do y2-y1/x2-x1 with what points?

  30. Michele_Laino
    • one year ago
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    yes!

  31. ashontae19
    • one year ago
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    with 5,5 and what other point?

  32. Michele_Laino
    • one year ago
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    it is the origin of the cartesian system, namely (0,0)

  33. ashontae19
    • one year ago
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    the slope would be 1 correct?

  34. Michele_Laino
    • one year ago
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    correct!

  35. Michele_Laino
    • one year ago
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    please wait, I have to answer to the phone

  36. ashontae19
    • one year ago
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    ok. when you get back just to ask is the equation y=x?

  37. Michele_Laino
    • one year ago
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    yes! correct!

  38. Michele_Laino
    • one year ago
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    now, you would write the coordinates of the subsequent four points: |dw:1443638327046:dw| namely the points at the top and at the bottom of each hill

  39. ashontae19
    • one year ago
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    ok so what would be the domain and range?

  40. ashontae19
    • one year ago
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    ok i did that @Michele_Laino

  41. Michele_Laino
    • one year ago
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    looking at your drawing I see that your roller coaster starts at the point (0,0) and continues to the point (16,1)

  42. Michele_Laino
    • one year ago
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    so the domain is the segment: \([0,16]\)

  43. Michele_Laino
    • one year ago
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    whereas the range is the segment \([0,5]\) approximately

  44. ashontae19
    • one year ago
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    ok what bout the rate of change?

  45. Michele_Laino
    • one year ago
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    the range is given by all possible values assumed by your function

  46. ashontae19
    • one year ago
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    for the rate of change?

  47. Michele_Laino
    • one year ago
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    in order to specify the rate of change we need of the subsequent ordered pair: |dw:1443639445403:dw|

  48. ashontae19
    • one year ago
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    pl= 10,2?

  49. ashontae19
    • one year ago
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    so was i corrected?

  50. Michele_Laino
    • one year ago
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    better is (10, 5/2)

  51. ashontae19
    • one year ago
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    i thought so . for pl= 10, 5/2 and for p2 is 12 ,2

  52. Michele_Laino
    • one year ago
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    better is (11.5, 1.5)=(23/2, 3/2)

  53. ashontae19
    • one year ago
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    thats for p1 and p2?

  54. Michele_Laino
    • one year ago
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    yes! now you have to do this computation: \[\huge r = \frac{{\frac{5}{2} - \frac{3}{2}}}{{10 - \frac{{23}}{2}}} = ...?\]

  55. ashontae19
    • one year ago
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    -183/20?

  56. Michele_Laino
    • one year ago
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    hint: \[\Large r = \frac{{\frac{5}{2} - \frac{3}{2}}}{{10 - \frac{{23}}{2}}} = \frac{1}{{\frac{{20 - 23}}{2}}} = \frac{2}{{20 - 23}} = ...?\]

  57. Michele_Laino
    • one year ago
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    furthermore you have to do a similar computation for the second hill

  58. Michele_Laino
    • one year ago
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    for question #7, here is my hint: |dw:1443642062352:dw| as you can see at the x-ccordinate x0 corresponds two distinct y-coordinate, namely y1 and y2. What can you conclude?

  59. Michele_Laino
    • one year ago
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    coordinate*

  60. ashontae19
    • one year ago
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    hi my internet working now @Michele_Laino

  61. ashontae19
    • one year ago
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    @Michele_Laino when ever you get online can you help me?

  62. Michele_Laino
    • one year ago
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    the first rate of change is: \[\Large r = \frac{{\frac{5}{2} - \frac{3}{2}}}{{10 - \frac{{23}}{2}}} = \frac{{\frac{2}{2}}}{{\frac{{20 - 23}}{2}}} = \frac{1}{{\frac{{ - 3}}{2}}} = 1 \cdot \left( { - \frac{2}{3}} \right) = ...?\]

  63. Michele_Laino
    • one year ago
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    please simplify

  64. Michele_Laino
    • one year ago
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    @ashontae19

  65. ashontae19
    • one year ago
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    -2/3?

  66. Michele_Laino
    • one year ago
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    yes! and for our computation we can take the absolute value, so the first rate of change is r=2/3

  67. Michele_Laino
    • one year ago
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    now we have to specify the points at the top and at the bottom of the second hill

  68. ashontae19
    • one year ago
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    so thats for the rate of change?

  69. Michele_Laino
    • one year ago
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    yes! it is the first rate of change, now we have to compute the rate of chage for second hill

  70. ashontae19
    • one year ago
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    yes

  71. Michele_Laino
    • one year ago
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    you have to write the coordinates of these points please: |dw:1443715743609:dw| referring your drawing

  72. ashontae19
    • one year ago
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    ok im going to send the picture to you

  73. Michele_Laino
    • one year ago
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    ok!

  74. Michele_Laino
    • one year ago
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    from your drawing we can see that the requested points are: (15,3) top of the hill (16,1) bottom of the hill

  75. ashontae19
    • one year ago
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    correct

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