Describe the graph of the function f(x) = x3 − 11x2 + 36x − 36. Include the y-intercept, x-intercepts, and the shape of the graph.

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Describe the graph of the function f(x) = x3 − 11x2 + 36x − 36. Include the y-intercept, x-intercepts, and the shape of the graph.

Algebra
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Other answers:

x-intercept is a point where line cross x-axis when y=0 so substitute y for 0 to find x-intercept y-intercept is a point where line cross y-axis when x=0 so substitute x for 0 to find y-intercept
but i dont see any y's so how can i make it a 0?
f(x) is same as y so it's \[\huge\rm y=x^3-11x^2+36x-36\]
oh ok
so when x=0 y=-36
right?
and for the shape when the highest degree is odd: if the leading coefficient is positive `Graph falls to the left and rises to the right` if the leading coefficient is negative then `graph rises to the left and falls to the right `
right
but how do i solve for y tho? @Nnesha
you already solved for y
not y i meant x
cause its 0=x3 − 11x2 + 36x − 36
factor by grouping and then set it equal to zero
(x - 2) • (x - 3) • (x - 6)
right
you still there
well u can't apply the group method
how did you get that ? calculator ?
ya
hmm alright set them equal to zero then solve for x
its -36
that's y-intercept
(x - 2) • (x - 3) • (x - 6)=0 so x-2 =0 x-3=0 x-6=0 now solve for x
so ad 2 6 and 3?
x=11
don't add
there supposed to be 3 x-intercepts bec highest degree is 3
oh ok
x=3 x=2 x=6
is that it
yes right
ok what is this last part Describe the graph of the function?
nvm we answered that already
thank you for the help
np

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